Question

Assume that you have a 32-bit MIPS processor with a direct mapped data cache with the capacity 4096 bytes and a block size of 16 bytes. The cache is initially empty (all valid bits are 0). Which sets of the cache have been updated after that the following program has been executed? For each of the sets, specify the set number, the value of the valid bit, and the tag value of the data cache. 1 lui $t0,0x12ff 2 lw $t1,0x1240($t0) 3 lw $t2,0x5aa4($t0) 4 lw $t3,0x4248($t0)

Answer 1

Einary 16 bit two complement for. decimal Integer this is a decimal to two's complement converter and two's compleme ar to decimal converter. these converters do not complement their Rep. input, that is, they do not negate. It they Just convert it to a from two's complement from torr- example -7 converts to 11111001 (to sbiro). Deunal to two's complement * enter a positive negative Integer * Set the number f bits for the two's complement Representsatt. * click convert to convert * click clear to Reset the form and start from be ratch. at you won to convert another Number, Just type over the original Number and

click convert there is no need to click clear first two complement to De linal x enter two's complement number a string & os and 15 & set the number of bits to match the length of the input. * Click convert to convert at * click clear to Reset the form and start from scratch - You can use tools complement to decinal to convert number that are Pn fixed-point two's complement nation for example: Pt you have 16-bit numbers in enter two's complement value, and then Junt divide the decimal Answer by 28 +5/28 = -128 to (215-1)/28 = 127.99009375 Here are some example: + 010111101010101 converts to 24405 and 24u05/28 -95.33 203/25 NO DI DIO ON convert to 10889 and -10889128 - -42.58515h

for ta convert bit pattern MERS TNS tractions the purpose f memory is to store groups of bits, and deliver. them upon demand most present-day computers store Information In nultiples fb bits, called by a byte. Most also 488ign anumeric address to each byre. this is convenient because Charakters can be stored in bytes. A word generally means the number f bits that can be transferred at one time on the data bus, and stored In a Register in the case { MIPS, a word is 32 bits, that is a byses. words are always stored an consecutive bytes, starting with an address that is divpsible by u. cautton other Processors, other definitionn. Me People prev bts as a word, to others it may nean. bu bits.

MIPS PS ifttle-endian, one Result & the Po that Character data appear to be stored "backward" within words. Here Pe la Representation of part of memory storing the characters "HOIP" (0x 70 60 6548) and then the Number 32766 (0x00007 fte) convert bit pattern to a mers Instruch 0000 000! Om OM 0100 1000 oop o000 0001 0001 Too) 0000 0000 0000 0001 100 * Decimal 3510 =3x10! + 5x 10°. * Bin989 010001121x25+12+ 1x & Hexadeunal 0423 37 23 400 = 2x611 + 3x160 Bor is Prary 0000 0001 0010 Hex 00 I Binary 0100 0101 010 011 OL 0011 03. 1000 08 11 00 od 1000 1110 ge 1010 ob. Dit. 10