Assembly Memory Segment Layout (Little Endian) - What does the "add" instruction do?
For example, on the first add instruction (add eax, 3), it moves the pointer for eax 3 spots to the right.
Thus, EAX = 12, 17, A3, 00. (This I understand)
But, on the second add instruction (add ebx, 5), it actually adds the value 5 to ebx, making EBX = 12, 17, A3, 05.
Why is that?
ANSWER:
varl var2 var3 dd 179 db 0A3h, 017h 012h bca var1 eax. mov add eax, mov ebx r [eax] add ebx 5 mov [varlj ebx B3 00 00 00 A3 17 12 62 63 61 var1 Va Va (4) (3) (3)
Assembly Memory Segment Layout (Little Endian) - What does the"add" instruction do?For example, on...
1. Assume that you are given values in eax, ebx, ecx. Write an assembly code that does the following: eax = (ecx + edx ) - (eax + ebx) 2. Write a piece of code that copies the number inside al to ch. Example: Assume that Initially eax = 0x15DBCB19. At the end of your code ecx = 0x00001900. Your code must be as efficient as possible. 3. You are given eax = 0x5. Write one line of code in...