Van der Waals equation-
substituting the values, we get:
or, (P + 2.785 atm)(1.088 L) = 20.43 L.atm
(P + 2.785 atm) = 18.78 atm
P = 15.99 atm
Therefore, Van der Waals pressure = 15.99 atm
Ideal gas pressure = 17.99 atm
Pideal - PVanderWaals = 17.99 - 15.99 = 2.00 atm
% difference = (2.00/17.99)x100 =11.11 %
According to the ideal gas law, a 0.9249 mol sample of xenon gas in a 1.135...
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