Given:
V = 0.8137 L
n = 10.01 mol
R = 0.08206 atm.L/mol.K
T = 500.4 K
a = 4.194 atm.L^2/mol^2
b = 0.05105 L/mol
use:
(P+an^2/V^2)*(V-nb) = n*R*T
(P + 4.194*10.01^2/0.8137^2)*(0.8137-10.01*0.05105) = 10.01*0.08206*500.4
(P + 634.6992)*(0.3027) = 411.0389
P + 634.6992 = 1357.9555
P = 723.3 atm
Difference = 723.3 atm - 505.1 atm
= 218.2 atm
% difference = (difference) * 100 / (actual)
Actual will be average of both the pressures
Actual = (723.3 atm + 505.1 atm) / 2
= 614.2 atm
Now use:
% difference = (difference) * 100 / (actual)
= 218.2 * 100 / 614.2
= 35.5 %
Answer: 35.5 %
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