If I mixed 100.0 mL of a nitric acid solution of pH = 2.40 with 100.0...

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Answer 1

Answer #1

Q.1) pH 1 = 2.4 [H+]= 0.0039M

pH 2 = 2.7 [H+] = 0.00199M

We know M1V1 +M2V2 = M3(V1+V2) ==>M3= 0.0028M

pH = -log [H+] = 2.55

Q.2) Molarity= number of moles×1000/volume in mL ==>M= 5.15×1000/241.86×150 = 0.142M

Answer 2

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