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What volume of 1.900-M NaOH should be added to 450. mL of 1.110-M solution of HCN...

What volume of 1.900-M NaOH should be added to 450. mL of 1.110-M solution of HCN (pKa = 9.40) to prepare a pH = 10.25 buffer? (use acid base table)

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Answer #1

- I moles of HeN = 1.110x 0.450 = 0.4995 mole 450,0 ml 1. до не No. of moles of HeN = 1.110. HCN + oH 0.4995 0.4995-x CN + H2No. of moles of cn form = 0.43 77 mole No. of moles of oth added = 0.4377 mole A ohimet 1.900 M Naot added: 0.4377 Togoo = 0.

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