Question

Men and women have lived in poverty since the beginning of time. Even today millions of people live below the poverty line. S
Linear: The number of dogs living as pets in households in the U.S. is shown in the graph below. Source: https://www.statista
in so 2000 2002 2004 2006 2008 2012 2014 2015 2017 1. Use the graph above to answer the following questions. a. With the exce
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Answer #1

Solution:

Given: Tabular Form for number of Men and Women under poverty line in different Year>

Year Men Women
2000 136.274 142.67
2001 137.558 143.917
2002 139.558 145.759
2003 140.931 146.768
2004 142.433 148.183
2005 143.803 149.331
2006 145.486 150.964
2007 146.655 152.004
2008 147.562 153.179
2009 149.237 154.582
2010 149.737 156.394

We have to find Line Regression Model for Men and Women as a function of time

If M,W represents dependent variable ie No. of Men, Women under poverty line

and t represents the year

we have

Regression Model as

M=a+bt

where

a = [(∑y)(∑x2)-(∑x)(∑xy)] / [n(∑x2)-(∑x)2]

b = [n(∑xy)-(∑x)(∑y)] / [n(∑x2)-(∑x)2]

solution for part (a) Linear regression model for men M as a function of time t

year(t) men(M) t*M t^2 M^2
2000 136.274 272548 4000000 18570.6
2001 137.558 275253.6 4004001 18922.2
2002 139.558 279395.1 4008004 19476.44
2003 140.931 282284.8 4012009 19861.55
2004 142.433 285435.7 4016016 20287.16
2005 143.803 288325 4020025 20679.3
2006 145.486 291844.9 4024036 21166.18
2007 146.655 294336.6 4028049 21507.69
2008 147.562 296304.5 4032064 21774.54
2009 149.237 299817.1 4036081 22271.68
2010 149.737 300971.4 4040100 22421.17
Sum 1579.234 3166517 44220385 226938.5

so with formula for a and b ie

a = [(∑y)(∑x2)-(∑x)(∑xy)] / [n(∑x2)-(∑x)2]

b = [n(∑xy)-(∑x)(∑y)] / [n(∑x2)-(∑x)2]

we have a= -2636.89 and b= 1.39

the regression model is

M=-2636.89 + 1.39t

solution for part (b) Linear regression model for Women M as a function of time t

year(t) women(W) W*t t^2 W^2
2000 142.67 285340 4000000 20354.73
2001 143.917 287977.9 4004001 20712.1
2002 145.759 291809.5 4008004 21245.69
2003 146.768 293976.3 4012009 21540.85
2004 148.183 296958.7 4016016 21958.2
2005 149.331 299408.7 4020025 22299.75
2006 150.964 302833.8 4024036 22790.13
2007 152.004 305072 4028049 23105.22
2008 153.179 307583.4 4032064 23463.81
2009 154.582 310555.2 4036081 23895.59
2010 156.394 314351.9 4040100 24459.08
Sum 1643.751 3295868 44220385 245825.1

so with formula for a and b ie

a = [(∑y)(∑x2)-(∑x)(∑xy)] / [n(∑x2)-(∑x)2]

b = [n(∑xy)-(∑x)(∑y)] / [n(∑x2)-(∑x)2]

we have a= -2526.20 and b= 1.33

the regression model is

M=-2526.20 + 1.33t

solution for part (c)

Rate of change for function from regression model comparing with y = mx + c, [ where m is slope(rate of change and c is intercept] is b

Rate of change for function for Men is 1.39

Rate of change for function for Women is 1.33

This shows that every year 1.39 men and 1.33 women goes below poverty line.

solution for part (d)

Intercept for function from regression model(comparing with y = mx + c, [where m is slope(rate of change) and c is intercept]is a

Intercept for function for Men is -2636.89

Rate of change for function for Women is -2526.20

This shows that at starting ie t=0 there were no men and women below poverty line(as number of men and women cannot be negative).

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