Question

13%) Problem 7: Consider a parallel plate capacitor having plates of area 1.4 cm2 that are separated by 0.016 mm of neoprene ubber. You may assume the rubber has a dielectric constant x 6.7 50% Part (a) what is the capacitance in 05 xAttempts Remain F? C 50% Part (b) what charge, Q, in coulombs, does it hold when 9.00 V is applied to it?

Answer 1

Capacitance is defined of c = element_r elementof_0 A/d A = 1.4 cm^2 d = 0.016 mm c = 8.85 times 10^-12 times 1.4 times 10^-4 /0.016 times 10^-3 times 6.7 = 774.37 times 10^-5 times 6.7 c = 51.88 mF theta = mv v = g. ovv theta = 51.88 mF times g theta = 466.92 mc