(8%) Problem 8: Consider a parallel plate capacitor having plates of area 0.000475 m² that are...
Find the capacitance of a parallel plate capacitor having plates of area 5.75 m2 that are separated by 0.495 mm of Teflon. The dielectric constant of Teflon is 2.1 X How is capacitance related to plate area and separation for a parallel plate capacitor? Did you consider the effect of the dielectric? HF
Find the capacitance of a parallel plate capacitor having plates of area 2.15 m2 that are separated by 0.220 mm of Teflon. The dielectric constant of Teflon is 2.1.
Consider a parallel plate capacitor having plates of area 0.00048 m^2 that are separated by 0.11 mm of Teflon. The dielectric constant of Teflon x = 2.1
Find the capacitance of a parallel plate capacitor having plates of area 2.95 m2 that are separated by 0.280 mm of Teflon. The dielectric constant of Teflon is 2.1. ______ uF
%) Problem 8: Considera parallel plate capacitor having plates of area0.000515m2 that are separated he dielectric constant of Teflon is x 2.1. à Find the capacitance in F Grade Summar Deductions Potential
Problem 7
(13%) Problem 7: Consider a parallel plate capacitor having plates of area 1.25 cm2 that are separated by 0.014 mm of neoprene rubber. You may assume the rubber has a dielectric constant K 6.7 50% Part (a) What is the capacitance in μF? Grade S Deductic Potential
Find the capacitance of a parallel plate capacitor having plates of area 4.00 m2 that are separated by 0.100 mm of Teflon. µF
Find the capacitance of a parallel plate capacitor having plates of area 1.00 m2 that are separated by 0.400 mm of Teflon. 1
Find the capacitance (in µF) of a parallel plate capacitor having plates of area 7.00 m2 that are separated by 0.300 mm of Teflon.
8) A parallel-plate capacitor consists of two parallel, square plates that have dimensions 1.0 cm, by 0 cm. If the plates are separated by 1.0 mm, and the space between them is filled with teflon, what is the capacitance? (The dielectric constant for teflon is 2.1.) A) 2.1 pF B) 0.89 pF C) 1.9 pF D) 0.44 p