If we tripled an ohmic wire RADIUS, then its resistance..?
The electrical resistance of a wire is given by
R = (p * L)/A
where,
R = Resistance of wire
p = Ressistivity of wire
L = length of wire
A = area of cross section = 3.14 *
(r)^2
where r = radius of wire.
If we triple radius,
Anew = 3.14 * (3*r)^2
Anew = 3.14 * r^2 * 9
Anew = 9 * A
Rnew = (p *
L)/Anew
Rnew = (p * L)/(A * 9)
Rnew = R/9
So we see, Resistance of the wire will reduce by the factor of
9.
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