Let "L" be the length of a wire, "r" be the radius of a wire & "R" be the resistance of a wire.
If the length and radius of this wire are doubled, then the new resistance will be given as -
drops to (1/2) its original value
Option (d) : it will be correct.
Explanation : we know that, R = L / A
where, A = cross-section area of a wire = r2
When the length and radius of this wire will be doubled, then we have
R' = (2 L) / [ (2r)2]
R' = (2 L) / (4 r2)
R' = (1/2) L / A
R' = (1/2) R
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