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5 pts) Does the Intermediate Value Theorem guarantee there is a zero in the interval [-2, 3] for the given function? (Show wh
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Answer #1

interval [ - 2 , 3 ]

f(x) = x^3 + 4x^2 - 1

f(-2) = (-2)^3 + 4(-2)^2 -1

f(-2) = - 8 + 16 -1

f(-2) = 7

f(3) = (3)^3 + 4(3)^2 - 1

f(3) = 62

as both values f(-2) and f(3) are positive

so,

the intermediate theorem does not guarantee there is a zero in the interval [ - 2 , 3 ]

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