Question

The number of accidents per week at a busy intersection was recorded for a year. There were 19 weeks with no accidents, 17 weeks with one accident, 9 weeks with two accidents, and 7 weeks with three accidents. A week is to be selected at random and the number of accidents noted. Let X be the outcome. Then X is a random variable taking on the values 0, 1, 2, and 3. (a) Write out a probability table for X (b) Compute E(X). (c) Interpret E(X). (a) Fill in the following probability table with the correct values. Outcomes 0 1 23 (Accidents per week) Probability D O D O (Type simplified fractions.)

Answer 1

isiven That 19 weeks oo accidents 17 weeks of accidents 9 weeks 02 accendents 7 Weeks 03 accendents since tatal weeks in normal year = 52 P(19 weeks) = o and P = PC) = 1 / 1 P(2) = 9/52 P(3) - 7/52 lo 1 2 3 های O ECX) = EXPCX) = 0 + 1x2 + 2x + 3 17+18+21= 56 - 14 52 52 C) Exs represents the average. no of accedents.