Binomial distribution: P(X) = nCx px qn-x
P(no accident on a day), p = 0.95
q = 1 - p = 0.05
a) P(no accident in next 7 days) = 0.957
= 0.6983
b) P(exactly 2 days with accident in next September) = 30C2 x 0.9528 x 0.052
= 0.2586
c) P(no accident in first 4 days but at least one accident by end of 10th day) = 0.954 x (1 - 0.956)
= 0.2158
d) Mean = np = 3
n x 0.05 = 3
n = 3/0.05
n = 60 days
4. The probability that there is no accident at a certain busy intersection is 95 %...
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