Question

4. The probability that there is no accident at a certain busy intersection is 95 % on any given day, independently of the ot
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Answer #1

Binomial distribution: P(X) = nCx px qn-x

P(no accident on a day), p = 0.95

q = 1 - p = 0.05

a) P(no accident in next 7 days) = 0.957

= 0.6983

b) P(exactly 2 days with accident in next September) = 30C2 x 0.9528 x 0.052

= 0.2586

c) P(no accident in first 4 days but at least one accident by end of 10th day) = 0.954 x (1 - 0.956)

= 0.2158

d) Mean = np = 3

n x 0.05 = 3

n = 3/0.05

n = 60 days

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