Show that the function y = cos (ln(x)] satisfies the differential equation 22 day dy +2...
4. (a Let (sin( x cos( ) dr + (x cos(x + y) - 2) dy. dz= Show that dz is an exact differential and determine the corresponding function f(x,y) Hence solve the differential equation = z sin( Cos( y) 2 x cos( y) dy 10] (b) Find the solution of the differential equation d2y dy 2 y e dx dæ2 initial conditions th that satisfi 1 (0) [15] and y(0) 0 4. (a Let (sin( x cos( ) dr...
Find the function y=y(x) (for x>0) which satisfies the separable differential equation dy/dx = (4+17x)/(xy^2). ;x>0 with the initial condition: y(1)=2
find the function y=y(x) for x>0 which satisfies the seperable differential equation, dy/dx=(4+17x)/(xy^2), x>0, y(1)=3
8. Find a solution to the differential equation dy 6x + sinx - 2 cos x that satisfies y (0) = 1 dx
Find the solution of the differential equation dy dx = x y that satisfies the initial condition y(0)=−7. Answer: y(x)=
Find the function y = y(2) (for x > 0) which satisfies the separable differential equation dy 6 + 14.2 dic 12 2 0 with the initial condition y(1) = 3. y=
(1 point) Solve the following differential equation: (tan(x) 8 sin(x) sin(y))dx + 8 cos(2) cos(y)dy = 0. = constant. help (formulas)
Solve differential equation. (x/y) (dx/dy) +(ln(y) - x) =0 I have been told it is not solved by substitution. It doesn't look exact or separable. It appears to be linear, but the mixed variable for qx and the natural log is confusing to me.
If a quantity y satisfies the differential equation dy = kx(10-y), k>0 dx. when X = 2 and y = -7, the graph of yir increasing decreasing constant cannot be determined
5. Find the solution of the differential equation that satisfies the given initial condition dy cos' xsin dx ysin y Yo) - 1. Leave the answer in the implici form. ,y(o)- 1. Leave the answer in the implicit form. 5. Find the solution of the differential equation that satisfies the given initial condition dy cos' xsin dx ysin y Yo) - 1. Leave the answer in the implici form. ,y(o)- 1. Leave the answer in the implicit form.