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Question 1: A. In a PN junction number of acceptors is NA = 1018 cm and Np = 4 x 1018 cm? a. Calculate the build in potential

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The given data is Acceptors (NA) = 1018 cm3 Donors (Nb) = 4x108 cm 3 is madeup 10 diode diode (he). Let us Asume PN - junihon1-3741 Vo VR 1 = 0.026 = 0.026( 37.42] = 0.97290 Vo= VB. I = Built in potential voltage Vo = 0.9729V Vo = 0.97 V o width um oedge region on the ² the depleton - pr side is lxp= w No NATNO 4*10 Xp - 3 mm 108+ 4x108 - 4x10 .3um too [144] X 3 mm = x 3

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