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From the standard potentials of the following half
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Answer #1

the most possitive value of E° will be REDUCED, since it has a higher potential to do so

the least E° value will be OXIDIZED

so

V3+ + e- = V+2 must be inverted, since it will NOT reduce

so:

PtCl62- + 2e- --> PtCl42- + 2Cl-

V2+ = V3+ + e-

balance electrons

PtCl62- + 2e- --> PtCl42- + 2Cl-

2V2+ = 2V3+ + 2e-

add all

PtCl62- + 2V2+ --> PtCl42- + 2Cl- + 2V3+

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