Question

7. Pug the penguin ride a cart along a track as shown in the figure. The graph shows the force exerted by Pug to propel the cart from point A to point B as a function of time. Pug is initially at rest at point A. The combined mass of Pug and the cart is 30.0 kg. FIN) 5 10 15 20 25 30 35 40 45 a) Calculate the work done by Pug as he moves from point A to point B on his cart. b) Calculate Pug's speed at point B. c) Pug reaches point C with a speed of 20.0 m/s. Calculate his speed at point D. Ignore friction along the slope from C to D. d) Pug reaches point E with a speed of 22.0 m/s and then travels around the circular track of radius R = 9.00 m to point F. Neglecting friction, calculate Pug's speed at point F. e) Calculate the force that the track exerts on the Pug-cart system at point F. Include a free- body diagram as part of your solution. f) What is the minimum speed the Pug-cart system could have at point F and stay on the track?

Answer 1

Solution) m = 30 kg (a) Work done, w=? The area under IF(N) 31 force - displacement o we work of slo is 20 25 30 35 Quo graph gives work There are three areas as shown, W=w,+ We ty W = (20-0)(18-0) +(4) (355-20) (15) + (2) (40-35) (-12) W = 382.5 W=382.5 speed at B. Vo = ? VA= 0 (rest) W=AKE = 1 n (v6²) - 1 m (VA) ² 382-5 = (²) (30) (Vg) ² - 0 - 2 = 382.5x2 = 255 - 30 VB = 525.5 = 5:049 ~ sios | VB = 5.05 ml Ve=20m/s (9 h = 20m

SKE = APE m (VG) ? - Įm(voje = mgh ( 1) (3-) (vo) - (4) (30) (20) = (3-) (9.5)( (15) (Vo)² - 6000 = 5 880 (15) (vo)² = 6000 + 5880 = 11880 (0)2 = 880 = 772 Yo=8792 = 28.14 10=28.1 m/s (d) VE = 2ml R=9 VF = ? At top , VF = MNE) - mg VE = (30) (2272 - (30) (9.1) m/s VF = 1319.3 questions in nent next post * kindly post