Question

 The percentage of recombinants observed among pairwise combinations of genes are as follows: A-C = 22 m.u., A-D = 5 m.u., B-D = 9 m.u., A-B = 4 m.u., B-C = 18 m.u. What is the order of these four genes?

 CDAB (BADC)

 BDAC (CADB)

 BCDA (ADCB)

 DBCA (ACBD)

 DCBA (ABCD

 CBAD (DABC)

 ADBC (CBDA)

 ABDC (CDBA

Answer 1

It's just because of recombination frequency one can find relative distance between the genes, both DABC and CBAD are correct. Hence, option f is correct.