Question

A wedge with a half-angle of 10 degrees is flying in Argon at M = 2. Find the ratio of total (stagnation) pressures across the shock wave emanating from the leading edge of the wedge.

Answer 1

2 sempront 1. The flow above the weekge is shesady The boundary Layer on the widgets Aire it on ideal pas curta center prife hou specific head of nate of ore 8-14 On the basis assumptin @ we tore the setem angle as equal to the wedge half coogle. very tho. curve Then two vaker of oblique shack colle para determined from the fetowiny expressen tomo = 2 (Mar sinep-1)/ turp may (k+ cos2p) +2 which is impercit in p. Therefore it by an iterative approach one from the pe We are to find out the angle of weak oblique shock Press & congle of Starry oblique shook. The props satished Looking from the grouph 34' Birny=2012 he con first pressure ratio Genoss the wear it Starry oblique shock. The pressure that case of story oblique they would te hyton point at may =2 cod o=320 strogihek

Strong shock 80 12 M1 M, -15 13 14 70 12.25 25 Inf -1 60 Shock wave angle, p (deg) Weak shock 30 20 10 10 15 35 40 45 50 20 25 30 Deflection angle, (deg)

The press une natte denon both strong and weak Shocks can be found out from the following empression P2 ar (Main) – r+1 P rtl where Main is the upstream normal macka Main = mas simpa which is For weak Shock (239) Main = 2 sin 390 = 1.2586 2x 1.4 (12586) - 1.4+1 Pewark 1.4 +1 4.035 1.6814 Ang For strory shore Pesten 840) Main = 280 (dy) = 1.989 2X 1.4x (1.989)2 – 1,4+1 strong 1.4+ 1 10.677 2.4 4.448 Any)
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