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QUESTION A wind tunnel has the below information, calculate, IF Average density of air, p =...
1. Consider a design of a low-speed open-circuit subsonic wind tunnel. The goal is to achieve...
1. Consider a design of a low-speed open-circuit subsonic wind tunnel. The goal is to achieve a free stream velocity of 150 m/s at the test section of this tunnel. This wind tunnel is equipped with a U-tube mercury manometer that measures the pressure difference between the inlet (the settling chamber) and the test section. If the fan of the wind tunnel is able to generate the maximum pressure difference corresponding to a height difference of 10 cm on the...
For the air wind tunnel shown Honeycomb Flow Straightener Anti-Turbulence Screens Silencer Fan Diffuser Test Section...
For the air wind tunnel shown Honeycomb Flow Straightener Anti-Turbulence Screens Silencer Fan Diffuser Test Section Inlet Assuming a circular cross section, the atmospheric pressure is 101.325 kPa, density of air is 1.2 kg/m?, and absolute viscosity of air is 1.825*10-S Ns/m? (assume there are no losses in the wind tunnel) Contraction ratio: 7 Diffuser length: 3 m Test section diameter = test section length = 70 cm a) When a static-pitot tube placed in the test section with a...
The closed-circuit wind tunnel flows air with a velocity of 200 fu's (between sections (5) and...
The closed-circuit wind tunnel flows air with a velocity of 200 fu's (between sections (5) and (6)] at standard condition. The picture and diagram of the wind tunnels are provided below. The flow is driven by a fan that essentially increases the static pressure by the amount Pi-P that is needed to overcome the head losses experienced by the fluid as it flows around the circuit. Determine the pressure rise ( P P ) Conditions) Assume air is incompressible (Mach...
9) For the air wind tunnel shown above in Q8: (6 points) Assuming a circular cross...
9) For the air wind tunnel shown above in Q8: (6 points) Assuming a circular cross section, the atmospheric pressure is 101.325 kPa, density of air is 1.2 kg/m², and absolute viscosity of air is 1.825*10-Ns/m² (assume there are no losses in the wind tunnel) Contraction ratio: 7 Diffuser length: 3 m Test section diameter = test section length = 70 cm a) When a static-pitot tube placed in the test section with a manometer (manometer fluid is water with...
5. The closed-circuit wind tunnel flows air with a velocity of 200 ft/s [between sections (5)...
5. The closed-circuit wind tunnel flows air with a velocity of 200 ft/s [between sections (5) and (6)] at standard condition. The picture and diagram of the wind tunnels are provided below. The flow is driven by a fan that essentially increases the static pressure by the amount pı - p9 that is needed to overcome the head losses experienced by the fluid as it flows around the circuit. Determine the pressure rise (pi - ps). Conditions) Assume air is...
8) (1 point) Honeycomb Flow Straightener -Anti-Turbulence Screens Silencer Diffuser Fan Test Section Inlet The wind...
8) (1 point) Honeycomb Flow Straightener -Anti-Turbulence Screens Silencer Diffuser Fan Test Section Inlet The wind tunnel shown above is; a) open circuit/suction/low speed wind tunnel b) open circuit/blow-down low speed wind tunnel c) closed circuit/suction/supersonic wind tunnel d) closed circuit/blow-down/supersonic wind tunnel 9) For the air wind tunnel shown above in Q8: (6 points) Assuming a circular cross section, the atmospheric pressure is 101.325 kPa, density of air is 1.2 kg/m², and absolute viscosity of air is 1.825*10-Ns/m² (assume...
8) (1 point) Honeycomb Flow Straightener -Anti-Turbulence Screens Silencer Fan Test Section Diffuser Inlet The wind...
8) (1 point) Honeycomb Flow Straightener -Anti-Turbulence Screens Silencer Fan Test Section Diffuser Inlet The wind tunnel shown above is; a) open circuit/suction/low speed wind tunnel b) open circuit/blow-down/low speed wind tunnel c) closed circuit/suction/supersonic wind tunnel d) closed circuit/blow-down/supersonic wind tunnel 9) For the air wind tunnel shown above in Q8: (6 points) Assuming a circular cross section, the atmospheric pressure is 101.325 kPa, density of air is 1.2 kg/m°, and absolute viscosity of air is 1.825*10-5 Ns/m² (assume...
Honeycomb Flow Straightener Anti-Turbulence Screens Silencer Fan Diffuser Test Section Inlet 9) For the air wind...
Honeycomb Flow Straightener Anti-Turbulence Screens Silencer Fan Diffuser Test Section Inlet 9) For the air wind tunnel shown above in Q8: (6 points) Assuming a circular cross section, the atmospheric pressure is 101.325 kPa, density of air is 1.2 kg/m², and absolute viscosity of air is 1.825*10-Ns/m² (assume there are no losses in the wind tunnel) Contraction ratio: 7| Diffuser length: 3 m Test section diameter = test section length = 70 cm a) When a static-pitot tube placed in...
Kindly correctly and show steps. Thank you 2. Wind (ρair = 1.225 kg/m3 ) passes through...
Kindly correctly and show steps. Thank you
2. Wind (ρair = 1.225 kg/m3 ) passes through a
turbine in Figure 2 at a constant temperature, whose blades of
length R1 = 30 m sweep out an area A1 seen in Figure 2.
V. P 1.5MW Figure 2: Wind Turbine. 2. (20 points) Wind (Pair1.225passes through a turbine in Figure 2 at a constant temperature, whose blades of length Ri 30 m sweep out an area A seen in Figure 2...
3. A wind turbine has blades, which sweep out an area of diameter 25 m 25m...
3. A wind turbine has blades, which sweep out an area of diameter 25 m 25m blades Fig. 5.1 (a) The wind is blowing directy towards the wind turbine at a speed of 12 m/s. At this wind speed, 7500 kg of air passes every second through the circular area swept out by the blades. U) Calculate the kinetic energy of the air travelling at 12 m /s, which passes through the circular area in 1 second Kinetic energy. The...
1. Consider a design of a low-speed open-circuit subsonic wind tunnel. The goal is to achieve a free stream velocity of 150 m/s at the test section of this tunnel. This wind tunnel is equipped with a U-tube mercury manometer that measures the pressure difference between the inlet (the settling chamber) and the test section. If the fan of the wind tunnel is able to generate the maximum pressure difference corresponding to a height difference of 10 cm on the...
For the air wind tunnel shown Honeycomb Flow Straightener Anti-Turbulence Screens Silencer Fan Diffuser Test Section Inlet Assuming a circular cross section, the atmospheric pressure is 101.325 kPa, density of air is 1.2 kg/m?, and absolute viscosity of air is 1.825*10-S Ns/m? (assume there are no losses in the wind tunnel) Contraction ratio: 7 Diffuser length: 3 m Test section diameter = test section length = 70 cm a) When a static-pitot tube placed in the test section with a...
The closed-circuit wind tunnel flows air with a velocity of 200 fu's (between sections (5) and (6)] at standard condition. The picture and diagram of the wind tunnels are provided below. The flow is driven by a fan that essentially increases the static pressure by the amount Pi-P that is needed to overcome the head losses experienced by the fluid as it flows around the circuit. Determine the pressure rise ( P P ) Conditions) Assume air is incompressible (Mach...
9) For the air wind tunnel shown above in Q8: (6 points) Assuming a circular cross section, the atmospheric pressure is 101.325 kPa, density of air is 1.2 kg/m², and absolute viscosity of air is 1.825*10-Ns/m² (assume there are no losses in the wind tunnel) Contraction ratio: 7 Diffuser length: 3 m Test section diameter = test section length = 70 cm a) When a static-pitot tube placed in the test section with a manometer (manometer fluid is water with...
5. The closed-circuit wind tunnel flows air with a velocity of 200 ft/s [between sections (5) and (6)] at standard condition. The picture and diagram of the wind tunnels are provided below. The flow is driven by a fan that essentially increases the static pressure by the amount pı - p9 that is needed to overcome the head losses experienced by the fluid as it flows around the circuit. Determine the pressure rise (pi - ps). Conditions) Assume air is...
8) (1 point) Honeycomb Flow Straightener -Anti-Turbulence Screens Silencer Diffuser Fan Test Section Inlet The wind tunnel shown above is; a) open circuit/suction/low speed wind tunnel b) open circuit/blow-down low speed wind tunnel c) closed circuit/suction/supersonic wind tunnel d) closed circuit/blow-down/supersonic wind tunnel 9) For the air wind tunnel shown above in Q8: (6 points) Assuming a circular cross section, the atmospheric pressure is 101.325 kPa, density of air is 1.2 kg/m², and absolute viscosity of air is 1.825*10-Ns/m² (assume...
8) (1 point) Honeycomb Flow Straightener -Anti-Turbulence Screens Silencer Fan Test Section Diffuser Inlet The wind tunnel shown above is; a) open circuit/suction/low speed wind tunnel b) open circuit/blow-down/low speed wind tunnel c) closed circuit/suction/supersonic wind tunnel d) closed circuit/blow-down/supersonic wind tunnel 9) For the air wind tunnel shown above in Q8: (6 points) Assuming a circular cross section, the atmospheric pressure is 101.325 kPa, density of air is 1.2 kg/m°, and absolute viscosity of air is 1.825*10-5 Ns/m² (assume...
Honeycomb Flow Straightener Anti-Turbulence Screens Silencer Fan Diffuser Test Section Inlet 9) For the air wind tunnel shown above in Q8: (6 points) Assuming a circular cross section, the atmospheric pressure is 101.325 kPa, density of air is 1.2 kg/m², and absolute viscosity of air is 1.825*10-Ns/m² (assume there are no losses in the wind tunnel) Contraction ratio: 7| Diffuser length: 3 m Test section diameter = test section length = 70 cm a) When a static-pitot tube placed in...
Kindly correctly and show steps. Thank you
2. Wind (ρair = 1.225 kg/m3 ) passes through a
turbine in Figure 2 at a constant temperature, whose blades of
length R1 = 30 m sweep out an area A1 seen in Figure 2.
V. P 1.5MW Figure 2: Wind Turbine. 2. (20 points) Wind (Pair1.225passes through a turbine in Figure 2 at a constant temperature, whose blades of length Ri 30 m sweep out an area A seen in Figure 2...
3. A wind turbine has blades, which sweep out an area of diameter 25 m 25m blades Fig. 5.1 (a) The wind is blowing directy towards the wind turbine at a speed of 12 m/s. At this wind speed, 7500 kg of air passes every second through the circular area swept out by the blades. U) Calculate the kinetic energy of the air travelling at 12 m /s, which passes through the circular area in 1 second Kinetic energy. The...
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