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PCO) = db) 1 CORRI The half-life of Palladium-100 is 4 days. After 12 days a...
The half-life of Palladium-100 is 4 days. After 20 days a sample of Palladium-100 has been...
The half-life of Palladium-100 is 4 days. After 20 days a sample of Palladium-100 has been reduced to a mass of 4 mg. What was the initial mass (in mg) of the sample? What is the mass 5 weeks after the start? Submit Question
please help! Question 28 < > 0/1 pt 5 3 3 99 Details The doubling period...
please help!
Question 28 < > 0/1 pt 5 3 3 99 Details The doubling period of a bacterial population is 20 minutes. At time t = 90 minutes, the bacterial population was 60000. What was the initial population at time t = 0? Find the size of the bacterial population after 3 hours. Question Help: D Video Submit Question Question 29 ^ B0/1 pt 53 99 Details The half-life of Palladium-100 is 4 days. After 24 days a sample...
Simplity. Enter the result as a single logarithm with a coefficient of 1. To enter the...
Simplity. Enter the result as a single logarithm with a coefficient of 1. To enter the log, click in the answer cell, then click on the small yellow arrow on the right. Then click the functions tab to access the log, if needed, you can change the base. Using the keyboard, you can also enter log, (52") as log 3/5x+4). lok. (*") + hoe (32) Question Help: Video Post to forum Question 41 B0/1pt2 Simplify. Enter the result as a...
Iron-59 is a radioisotope that is used to evaluate bone marrow function. The half-life of iron-59...
Iron-59 is a radioisotope that is used to evaluate bone marrow function. The half-life of iron-59 is 44.5 days. How much time is required for the activity of a sample of iron-59 to fall to 19.0 percent of its original value? days Submit Answer values if needed for this question. Thallium-201 is used medically to diagnose heart problems. The half-life of thallium-201 is 72.9 hours. If you begin with 37.2 mg of this isotope, what mass remains after 189 hours...
Question 4 1 pts A particular radioactive isotope has a half-life of 2.90 weeks. What fraction...
Question 4 1 pts A particular radioactive isotope has a half-life of 2.90 weeks. What fraction of the original sample is left after 101.5 days? 1/8 1/64 1/32 1/16 none of these Next
Radioactive Decay - Half-life and Activity 1 Radioactive decay - Half-life Time 0 1000 21 31...
Radioactive Decay - Half-life and Activity 1 Radioactive decay - Half-life Time 0 1000 21 31 750 N 1.000.000 500,000 250,000 125,000 62,500 31.250 15.625 7813 3.506 1.953 977 51 6 500 7 BI . 101 250 125 0 tie 21.234.41516171819, 1012 Time in multiples of A radioactive sample's half-life is 30.2 years. 1 year = 365 days, 1 day = 24 hours, 1 hour - 60 minutes, 1 minute = 60 seconds (a) Find its decay constant in year...
Questions 1-4 1.Calculate the mass defect and the binding energy/nucleon of the nuclide Be, which has...
Questions 1-4
1.Calculate the mass defect and the binding energy/nucleon of the nuclide Be, which has a mass of 9.012 182 24 amu. The mass of a proton is 1.007 276 47 amu and the mass of a neutron is 1.008 664 90. One amu - 1.6605 x 10 kg and the speed of light is 3.00 x 10 m/s. 2. Write the nuclear equation for each of the following reactions. Refer to a periodic table. a. the alpha decay...
Cesium-137, used in cancer treatment, has a half- life of 30 years. are here 1974 used...
Cesium-137, used in cancer treatment, has a half- life of 30 years. are here 1974 used in cancer treatment, has a half- Part A Enter the balanced nuclear equation for the beta decay (e) of cesium-137 Express your answer as a nuclear equation. Α. ΑΣφ on? Subrnit Previous Answers Request Answer Part B How many milligrams of a 24 mg sample of cesium-137 remain after 120 years? Express the mass to two significant figures and include the appropriate units. Value...
please help with b-d! *10-19-1 A radioactive sample's half-life is 30.2 years 1 year - 365...
please help with b-d!
*10-19-1 A radioactive sample's half-life is 30.2 years 1 year - 365 days, 1 day - 24 hours, 1 hour 60 minutes, 1 minute - 60 seconds (a) Find its decay constant in year 1. Keep 4 decimal places. 0.6229 Correct (100,0%) Submit Find its decay constant in sl. Write the result in terms of 10 10,9 Keep 4 decimal places. 7.2764 Correct (100.0 Submit Case 1: The Initial sample is 3.30 kg. (b) What is...
How to use C to output this: indigo1 376 % lab9 Capacity = 4 Capacity =...
How to use C to output this:
indigo1 376 % lab9
Capacity = 4
Capacity = 8
0 5 10 15 20
Capacity = 16
0 5 10 15 20 25 30 35 40
Capacity = 32
0 5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80
0 5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85 90 95 100 105
110 115 120 125...
The half-life of Palladium-100 is 4 days. After 20 days a sample of Palladium-100 has been reduced to a mass of 4 mg. What was the initial mass (in mg) of the sample? What is the mass 5 weeks after the start? Submit Question
please help!
Question 28 < > 0/1 pt 5 3 3 99 Details The doubling period of a bacterial population is 20 minutes. At time t = 90 minutes, the bacterial population was 60000. What was the initial population at time t = 0? Find the size of the bacterial population after 3 hours. Question Help: D Video Submit Question Question 29 ^ B0/1 pt 53 99 Details The half-life of Palladium-100 is 4 days. After 24 days a sample...
Simplity. Enter the result as a single logarithm with a coefficient of 1. To enter the log, click in the answer cell, then click on the small yellow arrow on the right. Then click the functions tab to access the log, if needed, you can change the base. Using the keyboard, you can also enter log, (52") as log 3/5x+4). lok. (*") + hoe (32) Question Help: Video Post to forum Question 41 B0/1pt2 Simplify. Enter the result as a...
Iron-59 is a radioisotope that is used to evaluate bone marrow function. The half-life of iron-59 is 44.5 days. How much time is required for the activity of a sample of iron-59 to fall to 19.0 percent of its original value? days Submit Answer values if needed for this question. Thallium-201 is used medically to diagnose heart problems. The half-life of thallium-201 is 72.9 hours. If you begin with 37.2 mg of this isotope, what mass remains after 189 hours...
Question 4 1 pts A particular radioactive isotope has a half-life of 2.90 weeks. What fraction of the original sample is left after 101.5 days? 1/8 1/64 1/32 1/16 none of these Next
Radioactive Decay - Half-life and Activity 1 Radioactive decay - Half-life Time 0 1000 21 31 750 N 1.000.000 500,000 250,000 125,000 62,500 31.250 15.625 7813 3.506 1.953 977 51 6 500 7 BI . 101 250 125 0 tie 21.234.41516171819, 1012 Time in multiples of A radioactive sample's half-life is 30.2 years. 1 year = 365 days, 1 day = 24 hours, 1 hour - 60 minutes, 1 minute = 60 seconds (a) Find its decay constant in year...
Questions 1-4
1.Calculate the mass defect and the binding energy/nucleon of the nuclide Be, which has a mass of 9.012 182 24 amu. The mass of a proton is 1.007 276 47 amu and the mass of a neutron is 1.008 664 90. One amu - 1.6605 x 10 kg and the speed of light is 3.00 x 10 m/s. 2. Write the nuclear equation for each of the following reactions. Refer to a periodic table. a. the alpha decay...
Cesium-137, used in cancer treatment, has a half- life of 30 years. are here 1974 used in cancer treatment, has a half- Part A Enter the balanced nuclear equation for the beta decay (e) of cesium-137 Express your answer as a nuclear equation. Α. ΑΣφ on? Subrnit Previous Answers Request Answer Part B How many milligrams of a 24 mg sample of cesium-137 remain after 120 years? Express the mass to two significant figures and include the appropriate units. Value...
please help with b-d!
*10-19-1 A radioactive sample's half-life is 30.2 years 1 year - 365 days, 1 day - 24 hours, 1 hour 60 minutes, 1 minute - 60 seconds (a) Find its decay constant in year 1. Keep 4 decimal places. 0.6229 Correct (100,0%) Submit Find its decay constant in sl. Write the result in terms of 10 10,9 Keep 4 decimal places. 7.2764 Correct (100.0 Submit Case 1: The Initial sample is 3.30 kg. (b) What is...
How to use C to output this:
indigo1 376 % lab9
Capacity = 4
Capacity = 8
0 5 10 15 20
Capacity = 16
0 5 10 15 20 25 30 35 40
Capacity = 32
0 5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80
0 5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85 90 95 100 105
110 115 120 125...
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