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An area with associated vector A -0.04961 +0.0543)+0.0291k is intersected by a uniform electric field E...
A flat surface of area 3.10 m2 is rotated in a uniform electric field of magnitude...
A flat surface of area 3.10 m2 is rotated in a
uniform electric field of magnitude E = 5.20 105 N/C.
(a) Determine the electric flux through this area when the
electric field is perpendicular to the surface.
N · m2/C
(b) Determine the electric flux through this area when the electric
field is parallel to the surface.
N · m2/C
Suppose a disk with area A is placed in a uniform electric field of magnitude E....
Suppose a disk with area A is placed in a uniform electric field of magnitude E. The disk is oriented so that the vector normal to its surface, n, makes an angle theta with the electric field as shown in the figure. Part A What is the electric flux Phi_E through the surface of the disk that is facing right (the normal vector to this surface is shown in the figure)? Assume that the presence of the disk does not...
A flat surface of area 2.60 m2 is rotated in a uniform electric field of magnitude...
A flat surface of area 2.60 m2 is rotated in a uniform electric field of magnitude E-5.90 x 105 N/C. (a) Determine the electric flux through this area when the electric field is perpendicular to the surface. The correct answer is not zero. N m2/C (b) Determine the electric flux through this area when the electric field is parallel to the surface. 15 34 Your response differs significantly from the correct answer. Rework your solution from the beginning and check...
(a) The electric field in a certain region is E (4.0)) N/C. Determine the electric flux...
(a) The electric field in a certain region is E (4.0)) N/C. Determine the electric flux due to this freld through an area represented by the vector A (1.51-7.k) m 29 How is the flux defined in terms of the electric field vector, and the area vector? Review dot product rules. N·m2/C (b) Determine the flux due to the same electric field when the surface orientation has changed such that the area is now represented by the vector A -(1.51-7.3)...
(a) The electric field in a certain region is E = (-4.0k) N/C. Determine the electric...
(a) The electric field in a certain region is E = (-4.0k) N/C. Determine the electric flux due to this field through an area represented by the vector A = (3.41 – 5.4K) m2. N- m²/c (b) Determine the flux due to the same electric field when the surface orientation has changed such that the area is now represented by the vector A = (3.4 - 5.49) m2. Nm2/C
(a) The electric field in a certain region is E = (-4,0 ) NC Determine the...
(a) The electric field in a certain region is E = (-4,0 ) NC Determine the electric flux due to this field through an area represented by the vector A = 4.8-5.0k) m2 (b) Determine the flux due to the same electric field when the surface orientation has changed such that the area is now represented by the vector A = (4.8↑-5.0j) m2. N m2/c
A square surface of area 5 cm2 is in a space of uniform electric field of...
A square surface of area 5 cm2 is in a space of uniform electric field of magnitude 104 N/C . The amount of flux through it depends on how the square is oriented relative to the direction of the electric field. Find the electric flux (in N · m2/C) through the square, when the normal to it makes the following angles with the electric field. Note that these angles can also be given as 180° + θ. (Enter the magnitudes.)...
A flat piece of cardboard with area 29.0 cm2 is immersed in a uniform electric field...
A flat piece of cardboard with area 29.0 cm2 is immersed in a uniform electric field of strength 1.40×103 N/C. If the angle between the field and the cardboard’s area vector is 56.0°, find the electric flux through the cardboard.
A uniform electric field of magnitude E = 465 N/C makes an angle of θ =...
A
uniform electric field of magnitude E = 465 N/C makes an angle of θ
= 61.5° with a plane surface of area A = 3.55 m2 as in the figure
below. Find the electric flux through this surface.
A uniform electric field of magnitude 3.50x104 N/C makes an angle of 47 ° with a...
A uniform electric field of magnitude 3.50x104 N/C makes an angle of 47 ° with a plane surface of area 1.63x10-2 m2 What is the electric flux through this surface? N m2/C Submit Request Ans
A flat surface of area 3.10 m2 is rotated in a
uniform electric field of magnitude E = 5.20 105 N/C.
(a) Determine the electric flux through this area when the
electric field is perpendicular to the surface.
N · m2/C
(b) Determine the electric flux through this area when the electric
field is parallel to the surface.
N · m2/C
Suppose a disk with area A is placed in a uniform electric field of magnitude E. The disk is oriented so that the vector normal to its surface, n, makes an angle theta with the electric field as shown in the figure. Part A What is the electric flux Phi_E through the surface of the disk that is facing right (the normal vector to this surface is shown in the figure)? Assume that the presence of the disk does not...
A flat surface of area 2.60 m2 is rotated in a uniform electric field of magnitude E-5.90 x 105 N/C. (a) Determine the electric flux through this area when the electric field is perpendicular to the surface. The correct answer is not zero. N m2/C (b) Determine the electric flux through this area when the electric field is parallel to the surface. 15 34 Your response differs significantly from the correct answer. Rework your solution from the beginning and check...
(a) The electric field in a certain region is E (4.0)) N/C. Determine the electric flux due to this freld through an area represented by the vector A (1.51-7.k) m 29 How is the flux defined in terms of the electric field vector, and the area vector? Review dot product rules. N·m2/C (b) Determine the flux due to the same electric field when the surface orientation has changed such that the area is now represented by the vector A -(1.51-7.3)...
(a) The electric field in a certain region is E = (-4.0k) N/C. Determine the electric flux due to this field through an area represented by the vector A = (3.41 – 5.4K) m2. N- m²/c (b) Determine the flux due to the same electric field when the surface orientation has changed such that the area is now represented by the vector A = (3.4 - 5.49) m2. Nm2/C
(a) The electric field in a certain region is E = (-4,0 ) NC Determine the electric flux due to this field through an area represented by the vector A = 4.8-5.0k) m2 (b) Determine the flux due to the same electric field when the surface orientation has changed such that the area is now represented by the vector A = (4.8↑-5.0j) m2. N m2/c
A
uniform electric field of magnitude E = 465 N/C makes an angle of θ
= 61.5° with a plane surface of area A = 3.55 m2 as in the figure
below. Find the electric flux through this surface.
A uniform electric field of magnitude 3.50x104 N/C makes an angle of 47 ° with a plane surface of area 1.63x10-2 m2 What is the electric flux through this surface? N m2/C Submit Request Ans
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