Question

The following table gives the average number of hours 5 junior high students were left unsupervised each day and their corresponding overall grade averages Hours Unsupervised 1 2 24 Overall Grades 63 77 91 96 98 Table Copy Data Step 1 of 5: Calculate the sum of squared errors (SSE). Use the values bo-66.3334 and bl = 9.3333 for the calculations. Round your answer to three decimal places ev Next

Answer 1

The statistical software output for this problem is:

Simple linear regression results:
Dependent Variable: Overall grades
Independent Variable: Hours
Overall grades = 66.333333 + 9.3333333 Hours
Sample size: 5
R (correlation coefficient) = 0.77331545
R-sq = 0.59801678
Estimate of error standard deviation: 10.821789

Parameter estimates:

Parameter	Estimate	Std. Err.	Alternative	DF	T-Stat	P-value
Intercept	66.333333	10.074537	? 0	3	6.5842562	0.0071
Slope	9.3333333	4.4179767	? 0	3	2.1125809	0.1251

Analysis of variance table for regression model:

Source	DF	SS	MS	F-stat	P-value
Model	1	522.66667	522.66667	4.4629981	0.1251
Error	3	351.33333	117.11111
Total	4	874

Hence,

Step - 1: SSE = 351.333

Step - 2: Estimated error variance = 117.111

Step - 3: Estimated variance of slope = 19.519

Step - 4: 98% confidence interval: (-10.727, 29.394)

Step - 5: 95% confidence interval: (-4.727, 23.393)