for open-closed pipe:
fn = (2n+1)*v/4L
f1 = v/4*L
= 350/(4*1.3)
= 67 Hz
f2 = 3v/4*L
= 3*350/(4*1.3)
= 200 Hz
f3 = 5v/4*L
= 5*350/(4*1.3)
= 340 Hz
If you model the tube as an open-closed system, what are the first three resonant frequencies?...
Parasaurolophus was a dinosaur whose distinguishing feature was a hollow crest on the head. The 1.6 - m - long hollow tube in the crest had connections to the nose and throat, leading some investigators to hypothesize that the tube was a resonant chamber for vocalization. If you model the tube as an open-closed system, what are the first three resonant frequencies? Assume a speed of sound of 350 m/s.
The lowest two resonant (standing wave) frequencies possible for a particular closed tube are 200 Hz apart. What is the frequency of the 1 st harmonic for this tube when both sides are opened? 200 Hz 250 Hz 300 Hz 350 Hz 400 Hz numbers 20-21 A 1.2 m closed tube resonates at the 5th harmonic. What is the wavelength? 0.84 m 0.96 m 1.08 m 1.20 m 1.32 m Which of the following distances from the open end will...
4) A tube with one open end and one closed end has á resonant frequency of 71.0 Hz. Find the length of the tube- and find the first three overtones. Use 343 m/s for the speed of sound.
12. A longitudinal standing wave can be created in a long, thin aluminum rod by stroking the rod with very dry fingers. This is often done as a physics demonstration, creating a high-pitched, very annoying whine. From a wave perspective, the standing wave is equivalent to a sound standing wave in an open-open tube. In particular, both ends of the rod are anti-nodes. What is the fundamental frequency of a 2.50 m -long aluminum rod? The speed of sound in...