Calculate the equilibrium constant K for the following reaction at 25 degrees celcius from standard electrode potentials for the following reaction:
Sn^4+(aq) + 2Hg(l) = Sn^2+(aq) + Hg2^2+(aq)
Calculate the equilibrium constant K for the following reaction at 25 degrees celcius from standard electrode...
Using std. electrode potentials listed, calculate the equilibrium constant at 25 ⁰C for the following reaction: O2 (g) + 4 H+ (aq) + 4 Fe2+ (aq) → 4 Fe3+ (aq) + 2 H2O (l) Fe3+ + e- = Fe2+ Ered= 0.77 O2 + 4H+ + 4e- = 2 H20 Ered= 1.23
Calculate the equilibrium constant for each of the reactions at 25∘C. Standard Electrode Potentials at 25 ∘C Reduction Half-Reaction E∘(V) Fe3+(aq)+3e− →Fe(s) -0.036 Sn2+(aq)+2e− →Sn(s) -0.14 Ni2+(aq)+2e− →Ni(s) -0.23 O2(g)+2H2O(l)+4e− →4OH−(aq) 0.40 Br2(l)+2e− →2Br− 1.09 I2(s)+2e− →2I− 0.54 A) 2Fe3+(aq)+3Sn(s)→2Fe(s)+3Sn2+(aq) (answers are not 4.1x10^5, 3.3x10^3, 2.7x10^10, or 2.6x10^10) B) O2(g)+2H2O(l)+2Ni(s)→4OH−(aq)+2Ni2+(aq) C) Br2(l)+2I−(aq)→2Br−(aq)+I2(s) (answer is not 1.7x10^18)
Calculate the equilibrium constant for each of the reactions at 25∘C∘C. Standard Electrode Potentials at 25 ∘C Reduction Half-Reaction Cl2(g)+2e ---> 2CI- 1.36 I2(s)+2e --> 2I- 0.54 Part A Cl2(g)+2I−(aq)→2Cl−(aq)+I2(s) K= ?
Calculate the equilibrium constant for each of the reactions at 25 ∘C. Standard Electrode Potentials at 25 ∘C Reduction Half-Reaction E∘(V) Pb2+(aq)+2e− →Pb(s) -0.13 Zn2+(aq)+2e− →Zn(s) -0.76 Br2(l)+2e− →2Br−(aq) 1.09 Cl2(g)+2e− →2Cl−(aq) 1.36 MnO2(s)+4H+(aq)+2e− →Mn2+(aq)+2H2O(l) 1.21 Pb2+(aq)+2e− →Pb(s) -0.13 Br2(l)+2Cl−(aq)→2Br−(aq)+Cl2(g) Express your answer using two significant figures.
Calculate the equilibrium constant of the following reaction
at 25 degrees Celsius data in the Table below.
Sn (s) + CuSO4 (aq)-->Cu (s) + SnSO4 (aq)
Using the reduction potentials given, calculate the equilibrium
constant, K, at 20 degrees C for the reaction
Using the reduction potentials given, calculate the equilibrium constant, K, at 25°C for the reaction, 33 3+ Ag (aa) t Fe(a)Ag) Fe (aq) +0.77 V +0.80 V A Ag+(aq) + e- ← a. 1.66 b. 6.4 c. 3.2 d. 6.1 x 10-4 e. 1.6 x 104 Rank the following compounds according to increasing solubility in water. K” is a less than sign) 34...
question 1 -
Use standard reduction potentials to calculate the equilibrium
constant for the reaction:
Fe3+(aq) +
Cu+(aq)
Fe2+(aq) +
Cu2+(aq)
Carry at least 5 significant figures during intermediate
calculations to avoid roundoff error when taking the
antilogarithm.
Equilibrium constant: ..... ?
G° for this
reaction would be greater or less than zero.?
question 2
Use standard reduction potentials to calculate the equilibrium
constant for the reaction:
2Cu2+(aq)
+ Hg(l)2Cu+(aq)
+ Hg2+(aq)
Carry at least 5 significant figures during intermediate...
Use standard reduction potentials to calculate the equilibrium
constant for the reaction:
2Cu2+(aq)
+ Hg(l)2Cu+(aq)
+ Hg2+(aq)
Hint: Carry at least 5 significant figures during intermediate
calculations to avoid round off error when taking the
antilogarithm.
Equilibrium constant... ?
G° for this
reaction would be greater or less than zero????
question 2
Use standard reduction potentials to calculate the equilibrium
constant for the reaction:
2Fe3+(aq)
+ Cu(s)2Fe2+(aq)
+ Cu2+(aq)
Hint: Carry at least 5 significant figures during intermediate
calculations to...
Cell Potential and Equilibrium Standard reduction potentials The equilibrium constant, K, for a redox reaction is related to the standard cell potential, Ecel, by the equation Reduction half-reaction (V) Ag+ (aq) + e-→Ag(s) Cu2+ (aq) + 2e-→Cu(s) 0.34 Sn (a) 4e-Sn(s 0.15 2H' (aq) + 2e-→H2 (g) Ni2+ (aq) + 2e-→Ni(s)-0.26 Fe2+ (aq) + 2e-→Fe(s)-0.45 Zn2+ (aq) + 2e-→Zn(s)-0.76 Al3+ (aq) +3e-→Al(s) -1.66 Mg2+ (aq) + 2e-→Mg(s) -2.37 0.80 n FEcell where n is the number of moles of electrons...
The equilibrium constant, K, for a redox reaction is related to the standard potential, Eº, by the equation In K = nFE° RT where n is the number of moles of electrons transferred, F (the Faraday constant) is equal to 96,500 C/(mol e), R (the gas constant) is equal to 8.314 J/(mol · K), and T is the Kelvin temperature. Standard reduction potentials Reduction half-reaction E° (V) Ag+ (aq) + e +Ag(s) 0.80 Cu²+ (aq) + 2e + Cu(s) 0.34...