no of moles of H2O = W/G.M.Wt
= 94/18 = 5.22moles
q1 = 94*4.18*(80-0) = 31433.6J = 31.4336KJ
q2 = n*H fus
= 5.22mole*6.01KJ/mole = 31.37KJ
q3 = mcT
= 94*2.09*30 = 5893.8J = 5.8938KJ
total heat release q = q1 + q2 + q3
= 31.4336+31.37+5.8938 = 68.7KJ
what is the amount of heat released when 94g of water at 80 degrees Celsius to...
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