Question

write a program that will read a file containing floating point numbers, store the numbers into an array, count how many numbers were in the file, then output the numbers in reverse order. Your program should only use one array and that array should not be changed after the numbers have been read. You should assume that the file does not contain more than 100 floating point numbers.

Numbers found in file

100.7362
105.2896
66.3493
105.6688
91.6180
64.8770
73.9249
87.3441
107.8753
108.2444
67.8807
108.5296
107.8583
84.2688
100.0140
67.0943
81.0881
105.7868
99.6104
107.9746
92.7870
61.7856
102.4565
106.6997
93.9368
97.8870
97.1566
79.6114
92.7739
68.5593
95.3023
61.5916
73.8461
62.3086
64.8566
101.1729
94.7414
75.8550
107.5111
61.7223
81.9372
79.0779
98.2758
99.7600
69.3436
84.4882
82.2793
92.3157
95.4682
97.7343
73.8013
93.9851
92.7549
68.1306
65.9499
84.9182
107.9872
77.0193
89.2634
71.1906
97.5634
72.7548
85.2979
94.9538
104.5452
107.9646
87.3608
66.9312
67.4647
72.8754
102.0359
72.7141
100.7142
72.1762
106.4632
77.4992
69.8298
72.5542
90.8022
83.6644
77.5830

Answer 1

HI, Please find my code.

Please let me know in case of any issue.

#include <iostream>
#include <fstream>
using namespace std;

int main(){

   string filename; // to store input file name
   ifstream inFile; // input stream

   cout<<"Enter input file name: ";
   cin>>filename;
  
   // opening file
   inFile.open(filename.c_str());

   // file opening error check
   if(inFile.fail()){
       cout<<"Error in file opening"<<endl;
       return -1;
   }

   //declaring a double array of size 100
   double data[100];
   int i = 0; // counter

   double number;

   // reading number one by one
   while(inFile>>number){
       // storing in array
       data[i++] = number;
   }

   // closing file
   inFile.close();

   // displaying in reverse order
   for(int j=i-1; j>=0; j--){
       cout<<data[j]<<" ";
   }
   cout<<endl;

   return 0;
}