Question 14 Q10B What are the partial fractions decomposition of 3x+2 +25x Sa+SX5 dx +ox (x-52...
- 2 + 6 Integrate -dx. 23 + 3x The partial fraction decomposition is (write all terms as fractions): dx The final answer is: dx = 23 + 3x Check Answer
Find the partial fraction decomposition for the rational expression. x + 7 3 25x - 16x x² + 7 3 25x-16x (Simplify your answer. Use integers or fractions for any numbers in the expre
2 ( numerator) x(x2-3x+2) ( denominator) The question is asking to; Resolve into partial fractions.
Write the partial fraction decomposition of the rational expression. 5x - 3 x² – 3x - 4 5x - 3 x² – 3x-4 (Use integers or fractions for any numbers in the expression.)
Question 1 2x+1 What is the form of the partial fractions decomposition for (2+1)?? А (2+1) B А (+1) + (x+1)? (x+1) Ar+B (x+1) ( stv
Dose 1.50) dx =7 (862) dx=15 (50) dx=9. 1'e() dv=3 14F(x)-2 g(x)) dx = is an odd function and is an even function Evaluate to (103dx = $(x) dx = 59(2) de T I Arial 3 (12pt] · TE E 5.00 1. P Question Completion Status: > A Moving to another question will save this response. Question 9 a , it Use Second Fundamental Theorem to find a Jo 0 ਨੰ: it = ਦੈਤ 0 , it = ਰੈੱਡ ©...
Q5). Integrate using Partial Fractions (show all working) 4x-8 dx x-2
3) Complete the Partial Fractions and find the indefinite integral r-3x5 +4x4 +2x3 10x2 +4x +8 x3(x 1)2(x +2)2 dx 3) Complete the Partial Fractions and find the indefinite integral r-3x5 +4x4 +2x3 10x2 +4x +8 x3(x 1)2(x +2)2 dx
Question 5 Use Partial Fractions to find A, B 223 +5x2+3x–8 2.x2+3x-2 A= -2, B=1 A=-2, B= 2 A= 2 , B= 1 O A=8, B=-1
x2-x+6 x3 +3x 7./Use the Apart command to decompose i into partial fractions. Question: which case is this?? Now find the antiderivative of each fractional expression by hand. Note: you will need to split apar of your fractions even further. You may use any of the shortcuts mentioned in Appendix G work below. t one . Show all x2-x+6 x3 +3x -11xs+914-222xx+39x+2 dx 8. Find the antiderivative: 3x6 -11x5 +9x4 -2x3 -x2 +9x -7 Make use of the Apart command,...