Question

QUESTION 6 A 275-9 sample of nickel metal is placed in 1000 g of water at 220 °C. Ater some time, the temperature of the water reaches 27 5°C What is the initial temperature of the nickel metal? Assume that no heat is lost toorged to the surroundings Specificheat capacity of nickel 0444 C ) * 294 "C 08240 403 od 7020 6100

Answer 1

Using energy conservation:

Energy gained by water = energy released by Nickel

Mass of Nickel = Mn = 275 g = 0.275 kg

mass of water = Mw = 100 g = 0.100 g

given final temperature is  = 27.5 C

Suppose initial temperature of Nickel = T

Q1 = energy gained by water = Mw*Cw*dT1

Q2 = energy released by Nickel = Mn*Cn*dT2

dT1 = 27.5 - 22.0 = 5.5 C

dT2 = T - 27.5

Cw = specific heat of water = 4186 J/kg-C

Cn = specific heat of Nickel = 444 J/kg-C

So,

0.100*4186*5.5 = 0.275*444*(T - 27.5)

0.275*444*T = 0.100*4186*5.5 + 0.275*444*27.5

T = (0.100*4186*5.5 + 0.275*444*27.5)/(0.275*444)

T = 46.4 C = Initial temperature of nickel metal

None of the given option is correct. Answer will be 46.4 C.

Please discuss this with your TA if there is no correct option.