Question

5. A random sample of 625 customers of the restaurant xyz revealed the average monthly expenses in the amount of € 43.50 with

0 0
Add a comment Improve this question Transcribed image text
Answer #1

a) a 95% confidence interval for the population mean expenses among xyz consumers

b)

c)

Add a comment
Know the answer?
Add Answer to:
5. A random sample of 625 customers of the restaurant xyz revealed the average monthly expenses...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A random sample of 13 customers in a Kentucky fast food restaurant revealed an average bill...

    A random sample of 13 customers in a Kentucky fast food restaurant revealed an average bill of OMR 18.75 per person. The population standard deviation is OMR5.4. Estimate 98% confidence interval for the mean bill of all customers. A random sample of ' n' customers in a Kentucky fast food restaurant revealed an average bill of OMR & per person. The population standard deviation is OMR 6. Estimate 98% confidence interval for the mean bill of all customers. n X...

  • In a random sample of 8 people with advanced degrees in biology, the mean monthly income...

    In a random sample of 8 people with advanced degrees in biology, the mean monthly income was $4744 and the standard deviation was $580. Assume the monthly incomes are normally distributed. Construct a 95% confidence interval for the population mean monthly income for people with advanced degrees in biology.

  • A quality control specialist for a restaurant chain takes a random sample of size 10 to...

    A quality control specialist for a restaurant chain takes a random sample of size 10 to check the amount of soda served in the 16 oz. serving size. The sample mean is 13.20 with a sample standard deviation of 1.51. Assume the underlying population is normally distributed. Find the 95% confidence interval for the true population mean for the amount of soda served.

  • A quality control specialist for a restaurant chain takes a random sample of size 10 to...

    A quality control specialist for a restaurant chain takes a random sample of size 10 to check the amount of soda served in the 16 oz. serving size. The sample mean is 13.60 with a sample standard deviation of 1.54. Assume the underlying population is normally distributed. Find the 95% confidence interval for the true population mean for the amount of soda served. (Round your answers to two decimal places.)

  • A test on a random sample of 50 water balloons yielded a sample average weight of...

    A test on a random sample of 50 water balloons yielded a sample average weight of 1.2 pounds. Prior studies have shown that the population standard deviation is 0.2 pounds. Assume that water balloon weight is normally distributed. Construct a 95% confidence interval of the population mean?

  • A random sample of 19 ​men's resting pulse rates showed a mean of 73.6 beats per...

    A random sample of 19 ​men's resting pulse rates showed a mean of 73.6 beats per minute and standard deviation of 18.2. Assume that pulse rates are Normally distributed. Use the table to complete parts​ (a) through​ (c) below. LOADING... Click the icon to view the​ t-table. a. Find a​ 95% confidence interval for the population mean pulse rate of​ men, and report it in a sentence. Choose the correct answer below​ and, if​ necessary, fill in the answer boxes...

  • The monthly incomes from a random sample of workers in a factory are shown below. Monthly...

    The monthly incomes from a random sample of workers in a factory are shown below. Monthly Income, in $1,000 4.0 5.0 7.0 5.0 6.0 6.0 10.0 8.0 9.0 (Please, avoid rounding intermediate steps and round your final solutions to at least 2 decimal places) Compute the 95% confidence interval for the mean monthly incomes of the workers. Provide the lower and upper bound of the interval below and give your answer in dollars. Are there any additional assumptions needed in...

  • 1. A random sample of size n is drawn from a population that is normally distributed...

    1. A random sample of size n is drawn from a population that is normally distributed with a standard deviation of 8. The sample mean is found to be 50. 1.a) Construct a 98% confidence interval (CI) for the population mean uif the sample size is 16. The critical value used is The (margin of) error for the 98% confidence interval (C.I.) is The resulting Cl is 1.b) Construct a 95% confidence interval for the population mean u if the...

  • Can Anyone help me with these 7 questions? Questions: Q1. A random sample has been taken...

    Can Anyone help me with these 7 questions? Questions: Q1. A random sample has been taken from a normal distribution and the following confidence intervals constructed using the same data: (38.02, 61.98) and (39.95, 60.05) (a) What is the value of the sample mean? (b) One of these intervals is a 95% CI and the other is a 90% CI. Which one is the 95% CI? Why? Q2. A civil engineer is analyzing the compressive strength of concrete. Compressive strength...

  • 5. The servicing time at the drive-through lane of a fast food restaurant follows an exponential distribution. The average servicing time is 2 minutes. (4 points) YORKVILLE BUSI 1013 statistics...

    5. The servicing time at the drive-through lane of a fast food restaurant follows an exponential distribution. The average servicing time is 2 minutes. (4 points) YORKVILLE BUSI 1013 statistics for Business What is the probability that it takes more than 2.5 minutes to service a customer at the drive-through lane? b. a. What percent of customers at the drive-through lane will take between 1 to 3 minutes to service? Part B 1. A simple random sample of 50 customers...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT