SOLUTION :
Let a grams be the weight over which 9% fruits are there.
P( x > a) = P( z > (a - m)/s)
=> 0.09 = P( z > (a - m)/s)
From ND table :
z > 1.34
The cutoff point is z = 1.34
So,
a = z * SD + m = 1.34 * 35 + 627 = 673.9 = 674 grams
So, the heaviest 9% fruits weigh more than 674 grams (ANSWER).
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