Ans :
Part 1 :
Each mole of pyrophyllite has 2 moles of Al atoms , according to the formula mentioned in the picture.
So 0.900 mol of the compound will have : 0.900 x 2 = 1.8 mol of Al
= 18 x 10-1 mol Al
Part 2 :
1 mole of mica has 3 moles of Al atoms
So 0.400 moles of Mica will have : 0.400 x 3 = 1.200 mol of Al
= 12 x 10-3 moles Al
Part 1 (0.3 point) 0.900 moles of pyrophyllite, Al2Si4010(OH)2 x 10 mol Al Part 2 (0.3...
Aluminum, silicon, and oxygen form minerals known as aluminosilicates. How many moles of aluminum are in: 1st attempt Part 1 (0.3 point) 210 moles of pyrophyllite, Al2Si4010(OH)2 mol Al Part 2 (0.3 point) 2.60 moles of mica, KAl3Si1(OH)2 moles Al Part 3 (0.3 point) 5.80 moles of albite, NaAlSi3O moles AI
2 Question (1 point) See page Aluminum, silicon, and oxygen form minerals known as aluminosilicates. How many moles of aluminum are in: 1st attempt Part 1 (0.3 point) See Periodic Table 1.65 moles of pyrophyllite, AlSi,O10(OH)2 mol Al Part 2 (0.3 point) mol Al Part 2 (0.3 point) 4.60 moles of mica, KAI:SizO10(OH)2 moles Al Part 3 (0.3 point) 1.40 moles of albite, NaAlSi Og moles Al
Part 3 (0.3 point) 7.00 moles of albite, NaAlSi30g moles Al
1) How many moles of Cu are in 257.58 g of Cu2O ? A) 0.900 mol B) 7.20 mol C) 3.60 mol D) 1.80 mol 2) How many moles of H2) are needed to produce 15.0 g of HCL (aq) in the following reaction? BCl3 (g) + 3 HCl (aq) > 3 HCl (aq) + B(OH)3 (aq) A) 5.0 mol B) 0.412 mol C) 0.137 mol D) 35.0 mol
Calculate the solubility (in moles per liter) of Al(OH)3 (Ksp = 2 x 10–32) in each of the following. a. water Solubility = mol/L b. a solution buffered at pH = 6.0 Solubility = mol/L c. a solution buffered at pH = 11.0 Solubility = mol/L
Calculate the solubility (in moles per liter) of Al(OH)3 (Ksp = 2 x 10-2) in each of the following. a. water Solubility = mol/L b. a solution buffered at pH = 5.0 Solubility = mol/L c. a solution buffered at pH = 10.0 Solubility = moll Submit Answer Try Another Version 6 item attempts remaining
Al(OH)3(s) → Al3+(aq) + 3OH−(aq) ΔfH∘/kJ⋅mol−1 −1284 −538.4 −230.02 S∘/J⋅mol−1⋅K−1 85.4 −325 -10.9 Part A Compute ΔrS (answer in J⋅mol−1⋅K−1) Part B Compute ΔrG∘ at 298 K (answer in kJ⋅mol−1) Part C Determine the equilibrium constant for the dissolution of Al(OH)3 at 298 K. Part D Determine the Gibbs energy change for the dissolution of Al(OH)3 when the concentrations of Al3+ and OH− are both 2.60×10−7mol⋅L−1.(answer in kJ⋅mol−1) Part E At what temperature will Al(OH)3(s) be at equilibrium with...
Complete and balance the reaction. X Не (aq) Al (OH) (s)3 AICI3(aq)+3H20() HCI(ад) (1 point) Part 2 Water is one of the products formed. Write the name (not the chemical formula) for the other product. aluminum chloride (1 point) Part 3 Write the net ionic equation. (aq), | б. X Не
#10 Calculate the solubility ( in moles per liter) of Al(OH)3 ( Ksp=2*10^-32) in each of the following. A. Water Solubility= B. a solution buffered at pH=4.0 C. a solution buffered at pH=9.0
Lequired HW 11/07/19 16 Question (1 point) The reaction of Cr2O3 with silicon metal at high temperatures will make chromium metal. 2Cr,0(s) +35i(s) — 4Cr(1) + 3Si0, (s) The reaction is begun with 98.00 g of Si and 78.00 g of Cr2O3- 1st attempt Part 1 (0.5 point) Select the limiting reactant. 15 OF 19 QUESTIONS COMPLETED < 16/19 > nk 12 pages Type here to search e ê 3 * Select the limiting reactant Choose one or more: В...