A superball and a clay ball are droped from a height of 10cm above a table top. They have the same mass 0.05kg and the same size. The superball bounces off the table and rises back to the same height. The clay ball sticks to the table. Match the shapes of the forces exerted on the superball and the clay ball by the table as a function of time.
For the superball in the previous question, if it was in contact with the table for 34.8ms, calculate the average force exertedon the ball by the table.
Hint: First calculate the momentum before and after hitting the table. Don't forget the gravitational force.
***THE ANSWER IS NOT 4.51.. I already tried that one
Potential energy becomes kinetic:
mgh = ½mv²
v = √(2gh)
so at impact v = √(2 * 9.8m/s² * 0.1m) = 1.4 m/s
You can't calculate the average force unless you have the time
interval. I'll take that as 34.8ms . Then
FΔt = mΔv
F * 0.0348s = 0.05kg * 2 *1.4m/s
F = 4.02 N
I hope it was helpful. Please rate me positive
A superball and a clay ball are droped from a height of 10cm above a table...
A superball and a clay ball are droped from a height of 10cm above a table top. They have the same mass 0.05kg and the same size. The superball bounces off the table and rises back to the same height. The clay ball sticks to the table. Match the shapes of the forces exerted on the superball and the clay ball by the table as a function of time. For the superball in the previous question, if it was in...
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