Question

Helloo Who can help with this problem

Consider the following DLX assembler program:
start: LW R1, 2020 (R0)
ADD R2, R0, R0
ADD R5, R0, R0
loop: LW R3, 1000 (R2)
ADDI R2, R2, # 4
SEQ R4, R1, R3
BEQZ R4, loop2
ADDI R5, R5, # 1
loop2: SEQI R4, R2, # 1000
BEQZ R4, loop
end: SW 2000 (R0), R5
STOP

Give in a short sentence what the program calculates
And do not forget to comment each line

Answer 1

start: LW R1, 2020 (R0)            @ Load value stored at 2020 mem locations away from value in R0
ADD R2, R0, R0                       @ Store in R2 twice of R0
ADD R5, R0, R0                       @ Store the same value in R5
loop: LW R3, 1000 (R2)               @ Mark this stateent as loop, load value stored 1000 mem location away from R2 in R3
ADDI R2, R2, # 4                   @ Add 4 to R2
SEQ R4, R1, R3                       @ If value in R1 and R3 are equal, set R4 to 1 else unset to 0
BEQZ R4, loop2                       @ If R4 is 0, go to loop2 statement, else continue from below statement.
ADDI R5, R5, # 1                   @ Increment R5 by 5 units.
loop2: SEQI R4, R2, # 1000           @ if R2 equals 1000, set R4 to 1 else unset to 0, statemenet marked at loop2
BEQZ R4, loop                        @ If R4 is equal to 0, branch to loop statement
end: SW 2000 (R0), R5               @ Store value in R5 to 2000 location away from value in R0
STOP                               @ End execution

This program increases R2 in every literation of loop, until R2 becomes 1000. In every iteration, R2 is incremented by 4 units. R3 is the value stored at 1000 units away from R2 value (which changes in each iteration). In every iteration, it also checks is R1 is equal to R3.. If it is, it increments R5 by 1. So basically if increments R5 when R1 matches R3., until R2 reaches 1000.

Hope the execution flow is clear now.