how would you do the convolution of d(t-1) and 2(1-e^-t)u(t) (d stands for the dirac delta function)
Please show steps. I know you have to delay the second function by 1 but I do not know if you would have to factor out the negative out of the exponential function first.
how would you do the convolution of d(t-1) and 2(1-e^-t)u(t) (d stands for the dirac delta...
In the following, x, (t)-Evenx(i), x,(1)-Odd{x(t): l n20 u(t)- «[n]- δ[n]-(0 otherwise δ(r) is the Dirac delta function
1. Evaluate and sketch the convolution integral (the output y(t)) for a system with input x(t) and impulse response h(t), where x(t) = u(1-2) and h(t)= "u(t) u(t) is the unit step function. Please show clearly all the necessary steps of convolution. Determine the values of the output y(t) at 1 = 0,1 = 3,1 = 00. (3 pts)
Please help. I need all steps, please do not use the delta dirac function as some other answers have for this question 4. (30 pts) A thick spherical shell (inner radius a, outer radius b) is made of dielectric material with a frozen-in polarization , where A is a constant, and r (x, y, z), r x2 +y2 + z2 is the vector and the distance from the center, respectively. (a) (10 pts) Calculate bound surface and volume charge densities...
answer 1,2,3,4 thank you. HW4.5: Problem 1 Previous Problem Problem List Next Problem 1 point) Evaluate each of the integrals (here &(t) is the Dirac delta function) (60-3)dt (2)cos(3t)S(t -2) dt- (3)/eTst cos(4t)(t - 3) dt - c0 sin()(t - 5) dt- HW4.5: Problem 1 Previous Problem Problem List Next Problem 1 point) Evaluate each of the integrals (here &(t) is the Dirac delta function) (60-3)dt (2)cos(3t)S(t -2) dt- (3)/eTst cos(4t)(t - 3) dt - c0 sin()(t - 5) dt-
So the time domain for this is v(t) = (1-cos(10pi))[u(t) - u(t-0.1)] + 2[u(t-0.1) - u(t-0.15)] + (-40t+0.2)[u(t-0.15) - u(t-0.25)] + (-2)[u(t-0.25)-u(t-0.3)] + (2e^(-5(t-0.3)))[u(t-0.3)] but the equation was reduced before converting into S-domain and it was reduced to : v(t) = (-cos(10pi))u(t) + u(t) + cos(10pi)u(t-0.1) + u(t-0.1) - 40(t-0.1))u(t-0.15) + 40(t-0.25)u(t-0.25) + 2u(t-0.3) + 2e^(-5(t-0.3))u(t-0.3) How do you adjust the time delay? Not sure if I understand how it was done, if you can show and explain step by...
I do not know how to factor this out. Can you please show the steps to help me out? 3) f(x) 3x4 22x3 13x2 118x 40; (3x 1) and (x 5)
MANE 315 Quiz#3 In Allen-Bradly PLC systems, you have a module with the product number。 explain 1) what t stands for? 2) What 'A' stands for? 3) What 8'stands for? (5) f "1746-1A 8.Please 2. In Allen-Bradly PLC systems, you have a module with the product number of "1746-0W 16". Please explain 1) what 'O, stands for? 2) What'W' stands for? 3) What' 16' stands for? (S) 3. Write the three positions of the key on PLC CPU, explain the...
Machine Desgin Problem The answer to the problem is: Delta 1=0.458 e-2 Delta 2=0.0715 Delta 3=0.044 Delta 4=0.75 e-4 Delta 5=0.214 Delta 6=0.034 Total Deflection=0.368 in Please show all work and steps For the wire of circular cross section below. find the deflection of point B in the direction of force using superposition. Assume a =4, b= 10" e = 10, F = 100 lbf, and dia. D= 0.75": E = 30 Mpsi: v = 0.3. Ignore the effect of...
For full credit, you must show all work and box answers 1. If functions f and g are piecewise continuous on the interval [0, oo), then the convolution of f and g is a function defined by the integral The Convolution Theorem (theorem 7.4.2 in your book and formula 6 in your table) states: If j(t) and g) are piecewise continuous on [0, oo) and of exponential order, then We are going to use convolution to solve y"-y,-t-e-,, y(0)-0, y'(0)-0....
I was able to find the first velocity by a=delta v / delta t, which = 40m/s for the first 5 seconds. How do you get the second velocity in order to draw that graph above? Please show work. A scientific package is attached to a balloon. Starting from rest on the ground, the balloon accelerates at a constant acceleration of 8 m/s straight upward for 5 seconds. The package is then released and undergoes a constant downward acceleration of...