So the time domain for this is v(t) = (1-cos(10pi))[u(t) - u(t-0.1)] + 2[u(t-0.1) - u(t-0.15)] + (-40t+0.2)[u(t-0.15) - u(t-0.25)] + (-2)[u(t-0.25)-u(t-0.3)] + (2e^(-5(t-0.3)))[u(t-0.3)]
but the equation was reduced before converting into S-domain and it was reduced to :
v(t) = (-cos(10pi))u(t) + u(t) + cos(10pi)u(t-0.1) + u(t-0.1) - 40(t-0.1))u(t-0.15) + 40(t-0.25)u(t-0.25) + 2u(t-0.3) + 2e^(-5(t-0.3))u(t-0.3)
How do you adjust the time delay? Not sure if I understand how it was done, if you can show and explain step by step how to get that answer please.
So the time domain for this is v(t) = (1-cos(10pi))[u(t) - u(t-0.1)] + 2[u(t-0.1) - u(t-0.15)] + ...
Verify the following using MATLAB 2) (a) Consider the following function f(t)=e"" sinwt u (t (1) .... Write the formula for Laplace transform. L[f)]=F(6) F(6))e"d Where f(t is the function in time domain. F(s) is the function in frequency domain Apply Laplace transform to equation 1. Le sin cot u()]F(s) Consider, f() sin wtu(t). From the frequency shifting theorem, L(e"f()F(s+a) (2) Apply Laplace transform to f(t). F,(s)sin ot u (t)e" "dt Define the step function, u(t u(t)= 1 fort >0...
Find the function of each graph u(x) and then u(t) and take the laplace transformation of u(t). Knowing that x=vt Profile one (step) 0.25 02 0.15 0.1 0.05 005 0.5 0.5 1.5 ength im) Profile two (ramp) 0.25 0.2 0.15 0.05 1.5 0.5 ength im Profile three (half-sine): 0.25 0.2 0.15 0.1 0.05 0.5 1.5 length m) Profile one (step) 0.25 02 0.15 0.1 0.05 005 0.5 0.5 1.5 ength im) Profile two (ramp) 0.25 0.2 0.15 0.05 1.5 0.5...
8 H 2 Q iL Vs (t 22 1. vs (t) 2 V; this is a dc source. Solve using a simple circuit analysis method 2. Us (t) 2u (t) V; solve by writing and solving the differential equation for the circuit, as in Ch. 8. You = = 0 for t0. can assume that ir 2u (t) V; solve using the Thévenin method, as in Ch. 8. You can assume that i, = 0 for t< 0. 3. vg...
Write the time domain function r(t) of the graph below as the sum of two rectangular pulse functions, then compute the fourier transform X(w) in terms of sinc function. (Reminder: A rectangular pulse centered 50,427 at the origin with width 27 is defined as II(t) = 11, -T<t<+T and it has the fourier transform II(t) sincwr)) 1 0 Amplitude -1 -2 0 2 3 8 9 10 11 5 6 7 Time-
Write the time domain function z(t) of the graph below as the sum of two rectangular pulse functions, then compute the fourier transform X(w) in terms of sinc function. (Reminder: A rectangular pulse centered fo.lt21 at the origin with width 27 is defined as II(t) = 11.-T <t< + and it has the fourier transform II(t) sinc(wr)) 3 2 Amplitude 0 0 1 2 3 4 5 6 7 8 9 10 11 Time
determine Laplace transform of a-d (a) f(1) = (1 - 4)u(t - 2) (b) g(t) = 2e-4eu(t - 1) (c) h(t) = 5 cos(2t - 1)u(t) (d) p(t) = 6[u(t - 2) - ut - 4)]
Question 11 pts x(t) is a time domain function. The laplace transform of x(t) is in what domain: s domain none of the above f domain time domain Flag this Question Question 21 pts if X(s) is the Laplace transform of x(t), then 's' is a : real number integer complex number rational number Flag this Question Question 31 pts In a unilateral Laplace transform the integral, the start time is just after origin (0+) just before origin (0-) origin...
i need these 2 question please it will be helpful thank u Document your solution to each problem. Clearly identify each step when solving a problem. 1. Find the Laplace transform off(t) when, K = 1. T1 =-27, =-1,73 = 1 and T.-3. 수 f(t) 2K 2. For the following functions, compute the Laplace transforms. You can use the tables for this question. a. f(t) (t) -2u(t) +u(t 1) b. g(t) 3e-C-u(t - 1) c. h (t) = 3 sin(t)...
12. Consider the standard second-order system with input as shown. t u(t 2 1n. G(s) Time (sec) a) Write the Laplace transform of the input signal. b) What is the transform of the output c Find the output of the system in time domain.
Find the Laplace transform of the following continuous-time signal. x(t)=2 e-*cos(30)u(t) Your answer: 5+1 X(s) = s? + 25 + 10 Ox(s) = 25+ 2 52 + 25 + 10 X(s)= 25+2 52 + 25 +9 o X(s)= 5 + 1 s²+25+9 X(s) = 35+3 52 +2s + 10