Stokes' law describes sedimentation of particles in liquids and can be used to measure viscosity. Particles in liquids achieve terminal velocity quickly. One can measure the time it takes for a particle to fall a certain distance and then use Stokes' law to calculate the viscosity of the liquid. Suppose a steel ball bearing (density 7.8 ✕ 103 kg/m3, diameter 3.2 mm) is dropped in a container of motor oil. It takes 11 s to fall a distance of 0.45 m. Calculate the viscosity (in kg/(m·s)) of the oil. Answer in Kg//(m*s)
Stokes' law describes sedimentation of particles in liquids and can be used to measure viscosity. Particles...
Stokes' law describes sedimentation of particles in liquids and can be used to measure viscosity. Particles in liquids achieve terminal velocity quickly. One can measure the time it takes for a particle to fall a certain distance and then use Stokes' law to calculate the viscosity of the liquid. Suppose a steel ball bearing (density 7.8 x 103 kg/m3, diameter 2.0 mm) is dropped in a container of motor oil. It takes 11 s to fall a distance of 0.65...
Problem #3 At very low Reynolds numbers a ball viscometer can be used to measure fluid viscosity by dropping a spherical ball in the fluid and measuring its terminal velocity. Consider a solid ball of radius a = 1cm and density Ps = 2,500 kg/m falling in liquid glycerin with density P = 1,250 kg/m3. The measured terminal velocity of the ball is U = 0.15 m/s. Calculate the viscosity of the liquid.
1) We use this formula: [Experimental value – Theoretical value]/ [Theoretical value] to calculate: Group of answer choices Atomic decay Biased Error Relative percent error Efficiency Redshift 2)You measure the diameter of a cylinder 5 times and get five different values (d1, d2, d3, d4, d5.) Then, the average value would be: Group of answer choices (d1 x d2 x d3 x d4 x d5) divided by 5 (d1 + d2 + d3 + d4 + d5) divided by 5...