Complete combustion of 3.129 g of a compound of carbon, hydrogen, and oxygen yielded 4.665 g CO2 and 1.433 g H2O. When 15.00 g of the compound was dissolved in 297 g of water, the freezing point of the solution was found to be -0.797 °C. For water, Kfp = 1.86 °C/m. What is the molecular formula of the compound?
Complete combustion of 3.129 g of a compound of carbon, hydrogen, and oxygen yielded 4.665 g...
Complete combustion of 4.251 g of a compound of carbon, hydrogen, and oxygen yielded 6.337 g CO2 and 1.946 g H2O. When 20.30 g of the compound was dissolved in 348 g of water, the freezing point of the solution was found to be -0.919 °C. For water, Kfp = 1.86 °C/m. What is the molecular formula of the compound? Enter the elements in the order C, H, O molecular formula =
Complete combustion of 8.293 g of a compound of carbon, hydrogen, and oxygen yielded 21.45 g CO2 and 4.391 g H2O. When 20.50 g of the compound was dissolved in 269 g of water, the freezing point of the solution was found to be -1.04 °C. For water, Kfp = 1.86 °C/m. What is the molecular formula of the compound? Enter the elements in the order C, H, O
A) The vapor pressure of an aqueous solution of potassium bromide at 31 °C is 0.04173 atm. The vapor pressure of pure water at the same temperature is 0.04434 atm. Estimate the freezing point of the solution. For water, Kfp = 1.86 °C/m. Answer:_____ °C B) Complete combustion of 3.769 g of a compound of carbon, hydrogen, and oxygen yielded 8.120 g CO2 and 3.325 g H2O. When 13.90 g of the compound was dissolved in 253 g of water,...
2. Combustion of 1.000 g of the compound that has carbon, oxygen and hydrogen yields 1.734 g CO, and 0.803 g H,O. In another experiment, 0.1067 g of the compound was dissolved in 23.6 g of water. This solution had a freezing point of -0.0914°C. What is the molecular formula of the compound?
2.516 g of a compound containing carbon, hydrogen and oxygen (CXHYOZ) is subjected to combustion analysis. The results show that 3.082 g of CO2 and 2.705 g of H2O were produced. (i). What is the empirical formula for the compound? (ii). If the molecular weight of the compound is 160.2 g/mol, what is the molecular formula of the compound?
A compound contains only carbon, hydrogen, and oxygen. Combustion of 10.68 mg of the compound yields 15.48 mg CO2 and 7.39 mg H2O. The molar mass of the compound is 182.2 g/mol. What are the empirical and molecular formulas of the compound? (Enter the elements in the order: C, H, O.) The empirical formula:? The molecular formula:?
Combustion analysis of 0.6943 g of an unknown compound containing carbon, hydrogen, and oxygen, produced 1.471 g CO2 and 0.226 g H2O. Determine the molecular formula, given the molar mass is 166 g/ mol.
The qualitative analysis of an organic compound showed C, H, O in combustion analysis of 0.20 34 g of a compound gave 0.5 911 g of CO2 and 0.10 36 g of H2O. the molecular weight of the compound was determined by the freezing point pressure method and was found in 210 from the above experimental results. determine the molecular formula of the compound 2. A compound is shown by qualitative analysis to contain carbon nitrogen oxygen and hydrogen combustion...
2. (2 Points) Cyanidin, contains carbon, hydrogen, and oxygen. The complete combustion of a 2.0000 g sample in excess O2 produces 4.5964 g CO2 and 0.6901 g H2O. Cyanidin's molecular mass is approximately 290 g/mol. What is the molecular formula of cyanidin?
5. (12 pts) A compound contains only carbon, hydrogen, and oxygen. If complete combustion of 70.86 g of this compound produces 103.9 g of CO2 and 42.52 g of H20, what is the molecular formula of this compound if it has a molar mass of 120.104 g/mol? (Carry each step to 3 digits after the decimal)