A string is stretched to a length of 406 cm and both ends are fixed. If...
Homework Answers
Solution)
Here,
Fundamental frequency, nf = 1 / 2L x square root ( T / m )
=( 1 / 2 x406 ) square root ( 924/0.0066)
= 0.4607 Hz.
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string is stretched to a length of 406 cm and both ends are fixed.
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