PROPERTIES OF MATERIALS Tempering is a heat treatment that is performed on: Austenite Pearlite Ferrite Martensite...
PROPERTIES OF MATERIALS
Tempering is a heat treatment that is performed on:
|
Austenite |
||
|
Pearlite |
||
|
Ferrite |
||
|
Martensite |
||
|
Cementite |
||
|
None of the above |
Homework Answers
Tempering is a heat treatment process to increase the toughness by sacrificing hardness of an alloy
it usually applies on iron alloys like cast iron, steel etc
Hence option C is correct
Add Answer to:
PROPERTIES OF MATERIALS
Tempering is a heat treatment that is performed on:
Austenite
Pearlite
Ferrite
Martensite...
7. A hypereutectoid steel contains 0.8% C. When slow cooled from austenite the following transformation products...
7. A hypereutectoid steel contains 0.8% C. When slow cooled from austenite the following transformation products result. a) ferrite and bainite b) ferrite and martensite c) ferrite and pearlite d) pearlite and cementite 8. Pearlite is a combination of a) cementite and iron carbide b) ferrite and cementite c) ferrite and bainite d) ferrite and martensite 9. The process of hardening steel consists of what two steps? a) melting the steel followed by quenching b) melting the steel followed by...
Quick these are multiple choices please 1000 1800 900 1600 Full annealing and hardening 800 A...
Quick these are multiple choices please
1000 1800 900 1600 Full annealing and hardening 800 A A1 Spheroidizing anneal-1200 Process anneal 600 1000 500 0 0.2 04 0.6 08 1.0 1.2 14 1.6 Figure 2: Summary of process beat treatments for steels on an equilibrium diagram. Question 3. (3Points) Using Figure 2 estimate the temperature (in "C) for a fall anneal of a low carbon Weight percent carbon steel? 1. 1650°C 2. 900°C 3. 600PC 4. 700°C Question 4. (3...
Austenite Pearlite Question 3 (24 pts): We are interested in performing different heat treatments to an...
Austenite Pearlite Question 3 (24 pts): We are interested in performing different heat treatments to an iron-carbon alloy of eutectoid compostion. Use the provided Temperature-Time Transformation (TTT) and Continuous Cooling Transformation (CCT) diagrams to specify the nature of the final microstructure in terms of microconstituents present and approximate percentages) of a small specimen that has been subjected to the following heat treatments. In each case, assume that the specimen begins at 760°C and that it has been at this temperature...
6.8. The heat treatments noted below are carried out in 1080 steel. In each case what phases will...
Phase, TTT, and CCT diagrams provided
6.8. The heat treatments noted below are carried out in 1080 steel. In each case what phases will be present at the end of the treatment? a. Austenitize at 750 deg C; quench to 0 deg C in 1s. b. Austenitize at 750 deg C; rapid quench to 650 deg C; isothermally anneal for 1000 s; quench to 0 deg C in 1s c. Austenitize at 750 deg C; very rapid quench to 250...
Describe the heat treatment scheume that would provide the following property changes to 1080 steel. Refer...
Describe the heat treatment scheume that would provide the
following property changes to 1080 steel. Refer to TTT diagram
below.
a) 100% pearlite to a miture of 50% pearlite and 50%
martensite
b) Mixture of 75% pearlite and 25% martensite to 100%
martensite
800 1400 Eutectoid temperature 700 1200 600 1000 500 800 400 600 300 M(start) M(50%) M(90%) 50% 400 200 M + A 100 200 0 10-1 102 Time (s) 10 103 10 10
Round to the nearest 5%--no need for something like 43.2...that would become 45. If there's none of that phase form...
Round to the nearest 5%--no need for something like 43.2...that
would become 45. If there's none of that phase formed, enter a 0
(zero). If it looks close enough then it is
800 1400 Eutectoid temperature 700 1200 1000 500 800 400 600 300 M(start) 200 400 M + A M( 5096) M19096) 100 10 102 03 104105 Time (s) Using the above TTT diagram for the eutectoid composition of steel, enter the relative amount of each microstructure formed for...
please answer question 2,3,4 A critical feature of steel is that a considerable amount of...
please answer question 2,3,4
A critical feature of steel is that a considerable amount of carbon can be dissolved in the austenite, phase, (up to 2.14 w/o at 1147"C), whereas carbon is essentially insoluble in ferrite, Cooling from point d to e, just above the eutectoid but still in the an increased fraction of the +y region, will produce phase and a microstructure similar to that shown: the particles precinitates out in the form af an intermetallic.compound called iron-carbide...
Q4.WHAT IS THE MECHANISIM WORKING HAREDING? .Q5.EXPLAINTHEMARTENZITIKTRANSFORMATION? Q6.EXPLAIN THE TEMPERING HEAT TREATMENT AND ITS BENEFITS?
Q4.WHAT IS THE MECHANISIM WORKING HAREDING? .Q5.EXPLAINTHEMARTENZITIKTRANSFORMATION? Q6.EXPLAIN THE TEMPERING HEAT TREATMENT AND ITS BENEFITS?
e. Quenching and Tempering as heat treatment processes f. Normalization and Annealing processes Question (3) For...
e. Quenching and Tempering as heat treatment processes f. Normalization and Annealing processes Question (3) For the shown bearing assembly submit the following - Specify certain type of fit between the shaft and bearing 2 degrees] - Specify certain type of fit between the bearing and housing 2 degrees
Its a thermal treatment of metallic materials from material science questions QUESTION 9 a) Heat treatment...
Its a thermal treatment of metallic materials from
material science questions
QUESTION 9 a) Heat treatment schedule for three (3) thin samples of plain carbon steel containing different carbon concentration is summarized in Table Q9(a). Determine and sketch the resultant microstructure for each steel. Distinguish steel 1 from steel 3 with reference to their mechanical properties. Table 29(a) Steel wt% C Heating temperature Soaking time (°C) (minutes) Cooling process 1 0.5 950 60 Furnace cooled 2 0.8 800 60 Air...
7. A hypereutectoid steel contains 0.8% C. When slow cooled from austenite the following transformation products result. a) ferrite and bainite b) ferrite and martensite c) ferrite and pearlite d) pearlite and cementite 8. Pearlite is a combination of a) cementite and iron carbide b) ferrite and cementite c) ferrite and bainite d) ferrite and martensite 9. The process of hardening steel consists of what two steps? a) melting the steel followed by quenching b) melting the steel followed by...
Quick these are multiple choices please
1000 1800 900 1600 Full annealing and hardening 800 A A1 Spheroidizing anneal-1200 Process anneal 600 1000 500 0 0.2 04 0.6 08 1.0 1.2 14 1.6 Figure 2: Summary of process beat treatments for steels on an equilibrium diagram. Question 3. (3Points) Using Figure 2 estimate the temperature (in "C) for a fall anneal of a low carbon Weight percent carbon steel? 1. 1650°C 2. 900°C 3. 600PC 4. 700°C Question 4. (3...
Austenite Pearlite Question 3 (24 pts): We are interested in performing different heat treatments to an iron-carbon alloy of eutectoid compostion. Use the provided Temperature-Time Transformation (TTT) and Continuous Cooling Transformation (CCT) diagrams to specify the nature of the final microstructure in terms of microconstituents present and approximate percentages) of a small specimen that has been subjected to the following heat treatments. In each case, assume that the specimen begins at 760°C and that it has been at this temperature...
Phase, TTT, and CCT diagrams provided
6.8. The heat treatments noted below are carried out in 1080 steel. In each case what phases will be present at the end of the treatment? a. Austenitize at 750 deg C; quench to 0 deg C in 1s. b. Austenitize at 750 deg C; rapid quench to 650 deg C; isothermally anneal for 1000 s; quench to 0 deg C in 1s c. Austenitize at 750 deg C; very rapid quench to 250...
Describe the heat treatment scheume that would provide the
following property changes to 1080 steel. Refer to TTT diagram
below.
a) 100% pearlite to a miture of 50% pearlite and 50%
martensite
b) Mixture of 75% pearlite and 25% martensite to 100%
martensite
800 1400 Eutectoid temperature 700 1200 600 1000 500 800 400 600 300 M(start) M(50%) M(90%) 50% 400 200 M + A 100 200 0 10-1 102 Time (s) 10 103 10 10
Round to the nearest 5%--no need for something like 43.2...that
would become 45. If there's none of that phase formed, enter a 0
(zero). If it looks close enough then it is
800 1400 Eutectoid temperature 700 1200 1000 500 800 400 600 300 M(start) 200 400 M + A M( 5096) M19096) 100 10 102 03 104105 Time (s) Using the above TTT diagram for the eutectoid composition of steel, enter the relative amount of each microstructure formed for...
please answer question 2,3,4
A critical feature of steel is that a considerable amount of carbon can be dissolved in the austenite, phase, (up to 2.14 w/o at 1147"C), whereas carbon is essentially insoluble in ferrite, Cooling from point d to e, just above the eutectoid but still in the an increased fraction of the +y region, will produce phase and a microstructure similar to that shown: the particles precinitates out in the form af an intermetallic.compound called iron-carbide...
e. Quenching and Tempering as heat treatment processes f. Normalization and Annealing processes Question (3) For the shown bearing assembly submit the following - Specify certain type of fit between the shaft and bearing 2 degrees] - Specify certain type of fit between the bearing and housing 2 degrees
Its a thermal treatment of metallic materials from
material science questions
QUESTION 9 a) Heat treatment schedule for three (3) thin samples of plain carbon steel containing different carbon concentration is summarized in Table Q9(a). Determine and sketch the resultant microstructure for each steel. Distinguish steel 1 from steel 3 with reference to their mechanical properties. Table 29(a) Steel wt% C Heating temperature Soaking time (°C) (minutes) Cooling process 1 0.5 950 60 Furnace cooled 2 0.8 800 60 Air...
Most questions answered within 3 hours.
-
.how important is it to use data modeling when designing
databases
asked 7 minutes ago -
A
child is siitng on a swing (20kg) and the mother applies a force of
45N...
asked 6 minutes ago -
Your university is running a special offer on tuition. This
year's tuition cost is $16,000. Next...
asked 5 minutes ago -
A massless and frictionless spring stretches 4.16 cm from the
relaxed position when a 1.47 N...
asked 10 minutes ago -
The United States nickel contains about 25% nickel metal and 75%
copper metal. Could you use...
asked 32 minutes ago -
what are the debuggers in Java?
import java.text.NumberFormat;
/**
*
* This class represents a circle...
asked 39 minutes ago -
the
financial statement that sums up a firm's revenues, costs, and
profit over a period of...
asked 38 minutes ago -
What are some of the chapter one and three key
words/concepts/topics (BOLD WORDS) in Operations Management...
asked 32 minutes ago -
Additive manufacturing (3-D printing) is an extension of:
computer-aided design.
modular design.
concurrent engineering.
quality function...
asked 35 minutes ago -
in python how to I get python to display 1 of 3 message every 45
seconds...
asked 58 minutes ago -
A hockey puck of mass 1 kg is traveling at 2 m/s in a direction
40º...
asked 55 minutes ago -
Assume you are the holder of a call option on €10,000. The
option premium is $0.25...
asked 57 minutes ago