pl#3
QUESTION 1
QUESTION 2
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QUESTION 4
PL#4
QUESTION 1
QUESTION 2
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QUESTION 6
#3
Digestion of precipitate means that dissolution of precipitate. When precipitate in a solution dissove completely and give a clear solution then we can say that the precipitate is digested. It may occur some external factor like temperature and adding some chemical species.
#4
If 2 drops are good then 20 drops will be better is chemically wrong statement. Actually phenolphthalein has its own pH working range and dissociation when we add 20 drops of it it will affect the resulting pH of the solution or mixture by forming HIn compound and the end point will be affected at par. So excess addition will cause wrong end point of titration.
pl#3 QUESTION 1 A mixture of 0.810g of BaCl 2.2H 2O and Na 2SO 4 produces...
Part A: Standardization of NaOH Solution Data Table: Trial 1 Trial 2 Trial 3 Tared mass of KHP (g) 5065 -S168 so40 Molar mass of KHP (g/mol) 204.23 204.23 204.23 Moles of KHP (mol) Buret Reading:Initial Volume of NaOH (mL) .3 23. 2 나6.2. Buret Reading: Final Volume of NaOH (mL) Volume of NaOH dispensed (mL) Molar concentration of NaOH (mol/L) Average Molar concentration of NaOH 28.3 22.1 1145 O533 ces 3 (mol/L) Experiment: Volumetric Analvsis
Question 1 (2 points) How many moles of KHP are contained in a sample of 4.656 g KHP (Molar Mass = 204.22 g/mol)? 0.0228 moles KHP 0.0656 moles KHP 4656 moles KHP 0.0114 moles HD Question 2 (2 points) If the reaction between KHP and NaOH is: C8H.KOH + NaOH - H2O + CHAKO Na (KHP) How many moles of NaOH are needed to react with 4.656 g of KHP?! 0.0656 moles NaOH 0.0228 moles NaOH 0.0114 moles NaOH 4.656...
I need help with question #1 and 2 under Post Lab based on the Data Table 1. I appreciate the help. 4. Complete Data Table 1. The neutralization reaction between HP and NaOH : 1o Espon por Adobe PDF KHC,H,O (aq) + NaOH(aq) + KNBCH40 (aq) + H301) Data Table 1. Standardization of NaOH solution Trial 1 Trial 2 Trial Volume of 0.500 M KHP, ml 41.552mL 41.276m 39.169 mL Buret reading before titration, mi. 2.00 2.00 ML 2.00ml Buret...
i need help with these three questions Incorrect Question 2 0/1.25 pts 0.678 g of KHP is used to standardize a NaOH solution. If it took 31.55 mL of NaOH to neutralize the KHP, what is the concentration of the NaOH solution? The molar mass of KHP is 204.22 g/mol. KHP + NaOH --> NaKP + H2O Give the answer to 3 sig figs and use units of M 0.0214 Unanswered Question 3 0/1.25 pts A 25.00 mL HCl sample...
7-10 1. Tared mass of KHC.H.O.) 2 Mar THIRSS C KIICH 04. 3 Miles of KHC H40(Pro) Titration apparatus approval 4. Buret reading of NaOH, initial (mL) 19,3 mL 19.3 mL 5. Buret reading of NaOH, final (mL) 19 3 mil 6. Volume of NaOH dispensed (mL) 7. Molar concentration of NaOH (moVL) Data Analysis, B 8. Average molar concentration of NaOH (mol/L) Data Analysis, 9. Standard deviation of molar concentration Data Analysis, B 10. Relative standard deviation of molar...
Acid / Base Titrations: Pre-Laboratory Assignment 1. Give at least two characteristics desirable in a primary standard. 2. Define equivalence point and ritration and point. Do these two points in a titration occur when the same volume of titrant has been added? Explain 3. A student standardized a NaOH solution using KHC.H.O.. Three different KHC&H.O. samples were dissolved in water and titrated with the same NaOH solution, each to a phenolphthalein end point. The pertinent reaction is: KHC H404 aq)...
PRE LAB : Volumetric Titrations. (Acid-Base Titrations) Name: ID Date 1. How many mL of a 0.103M NaOH solution are required to neutralize 10.00mL of a 0.198M HCI solution? 2. what is the difference between end point and equivalence point? 3. A titration is performed and 20.70 mL of 0.500M KOH is required to reach the end point when titrated against 15.00 mL of H2SO4 of unknown concentration. Write the chemical equation and solve for the molarity of the acid....
The table filled is the lab run. Please can you use the three informations provided above to answer the empty table Take Density of vinegar = 1.005g/mol concentration of NaOH = 0.1205M Experiment #7. Titration of Vinegar Goals 1. To determine the mass percent of acetic acid in a solution via titration. 2. To master the technique of titration. Introduction Vinegar is a common household item that is found in a number of products from salad dressing to cleaners. Vinegar...
What would be for the mol reacted,, mol NH4X in sample, and yhr average molar mass? CALCULATIONS A. NaOH Preparation: Approximate molarity of NaOH 0.48 M B. NaOH Standardization: Trial # Mass of KHP E 1.7249 1.9569 1.8799 Volume of NaOH 18.58 L 20.58mLihat 19.71 mL Molarity of NaOH 0.4544 M 0.4654M 0. 3 M 0.4668M Average molarity of NaOH: 0.4668 M 0.4622 M C. Molar Mass of NH X Salt 1. Volume of NaOH 0.025 0.025 0.025L 2. Molarity...
4. Vinegar is a solution of acetic acid. Acetic acid has a 1:1 ratio when reacted with NaOH. a. Suppose that the molarity of acetic acid in vinegar is 0.5 M, how many grams of acetic acid are present in the 5 ml of vinegar solution used in the titration? (molar mass of acetic acid = 60 g/mol). b. If vinegar has a density of 1.01 g/mol. Calculate the % of acetic acid in vinegar by mass. 5. 50 ml...