62% of Americans like a certain car brand
Margin of error is 5.5%
Confidence Level is 95%
a) Find the number of people surveyed
Choose
a) 77 b) 100 c) 300 d)600 e)1200
b)What is the 90% confidence interval for the population proportion who like the car brand.
a) (5%, 95%) b) (10%, 90%) c) (56.5%, 67.5%) d) (57.4%, 66.6%) e) (53%, 71%)
a. Here z value for 95% CI is 1.96 as P(-1.96<z<1.96)=0.95
Margin of Error is E=0.055 and p=0.62
So we will find n using formula of E,
So
Hence answer is c) 300
b. z value for 90% CI is 1.645 as P(-1.645<z<1.645)=0.90
So Margin of Error is
Hence CI is
Hence answer here is d) (57.4%, 66.6%)
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7.1
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