We are given here that:
P( 0 < Z < z ) = 0.4901
Therefore P(Z < z) = P(Z < 0) + P(0 < Z < z ) = 0.5 + 0.4901 = 0.9901
From standard normal tables, we have:
P( Z < 2.33) = 0.9901
Therefore +2.33 is the required z value here.
For a standard normal distribution, find the value of z such that: P(0<Z<z) = 0.4901 A....
Provide an appropriate response. Use the standard normal distribution to find P(z < -2.33 or z> 2.33). Select one: OA. 0.0198 B. 0.0606 OC. 0.7888 0 D. 0.9802
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Given a standard normal distribution, find the value of k such that (a) P(Z > k) = 0.3050; (b) P(Z <k) = 0.0367 (c) P(-0.96 <Z <k) = 0.7221 Click here to view page 1 of the standard normal distribution table Click here to view page 2 of the standard normal distribution table (a) k= (Round to two decimal places as needed.) (b) k = (Round to two decimal places as needed.) (c) k= (Round to two decimal places as...
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Let z have a normal standard distribution. Determine the value of Zc. P(0 < Z < Zc)=0.4573
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