Let z have a normal standard distribution. Determine the value of Zc.
P(0 < Z < Zc)=0.4573
P(0 < Z < Zc)=0.4573
p(Z<Zc) - p(Z<0) = 0.4573
p(Z<Zc) -0.5= 0.4573
p(Z<Zc) = 0.9573
using inverse normal probability distribution
p(Z<1.72) = 0.9573
Ans: Zc = 1.72
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