Assume that Z represents a standard normal random
variable.
(a) Find P(Z < 1.38)
(b) Find P(Z > 2.02)
(c) Find P(Z < -1.8)
(d) Find P(0.42 < Z < 1.39)
(e) Find c, so that P(Z < c) = 0.90
Assume that Z represents a standard normal random variable. (a) Find P(Z < 1.38) (b) Find...
(1 point) Find the following probabilities for the standard normal random variable z. (a) P(-0.81 <<0.42) (b) P(-1.14 <z < 0.5) (c) P(Z < 0.69) a (d) P(Z > -0.6)
1. Given that z is a standard normal random variable, compute the following probabilities. a. P(Z < 1.38) b. P(z 2 1.32) c. P(-1.23 Sz5 1.23)
Z is a standard normal random variable, then P =... a. P(Z < 1.37) = b. P(Z > −1.51) = c. P(−1.031 < Z < 1.92) = d. P(0.00 < Z < 1.79) = e. (A-Grade) P(Z = 0.518) =
1. Let Z be the standard normal random variable. Find (a) P(Z > −1.78) = (b) P(−.60 < Z < 1.25) = (c) z.005 = (d) z.025 =
IS Find the following probability for the standard normal random variable z. a. P(z<-1.02) b. P(z <2.03) c. P(0.68 szs2.03) d. P(-2.66szs1.56) a. P(z -1.02)(Round to four decimal places as needed.) b. Pize 2.03)=[] (Round to four decimal places as needed.) ook c. P(0.68 szs2.03) (Round to four decimal places as needed.) d.P(-2.66 s zs 1.56) = [□ (Round to four decimal places as needed.)
Find a value of the standard normal random variable z, call it zo, such that the following probabilities are satisfied a. P(zszo)-0.0483 e. P(-Zo szs0) 0.2945 f.Pl_3czczo)#0.9533 c. P(-20 5zszo)-0.90 d. P(-20 5z5zo)-0.8462 h. P(ZSZo)-0.0049
2. Random variable Z has the standard normal distribution. Find the following probabilities a): P[Z > 2] b) : P[0.67 <z c): P[Z > -1.32] d): P(Z > 1.96] e): P[-1 <Z <2] : P[-2.4 < Z < -1.2] g): P[Z-0.5) 3. Random variable 2 has the standard normal distribution. Find the values from the following probabilities. a): P[Z > 2) - 0.431 b): P[:<] -0.121 c): P[Z > 2] = 0.978 d): P[2] > 2] -0.001 e): P[- <Z...
Find the probability of the standard normal random variable Z. P(Z < 1.49) A) 0.9319 B) 0.0681 C) 0.6879 D) 0.3121
Find a value of the standard normal random variable z, call it 20, such that the following probabilities are satisfied. a. P(zszo)=0.0502 b. P(-2o Szszo)=0.99 c. P(-zo szszo)=0.90 d. P(- zo szszo) = 0.8062 e. P(-Zo Szs 0) = 0.2593 f. P(-3<z<zo)=0.9654 g. Plz>20) = 0.5 h. Plz szo) = 0.0088
If Z is a standard normal random variable, then find: a. P(Z ≤ z), where z= 1.24 b. P(a ≤ Z ≤b), where a= 0.55 and b=1.33 c. find P(Z ≥ z), where z= 0.38 d. A value for z for which P(Z > z) = 0.8264