In another laparoscopic surgery, helium is used to inflate the abdomen to separate the internal organs...

Question

Question

In another laparoscopic surgery, helium is used to inflate the abdomen to separate the internal organs...

In another laparoscopic surgery, helium is used to inflate the abdomen to separate the internal

organs

and the abdominal wall. If the He injected into the abdomen produces a pressure of 15 mmHg and a

volume of 3.1 L at 28 °C, how many grams

of He were used

science chemistry

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Answer 1

Answer #1

from ideal gas equation, PV = nRT

But n= mass/molar mass ======> PV = (mass/molar mass)*RT

P = Total pressure = 15 mm of Hg

V = volume of gas mixture = 3.1 L

R = 0.0821 l.atm.k-1.mol-1

T = 28 c= 301 k

Mass of He used = PV *molar mass/ RT = 15*3.1*4/(760*0.0821*301) = 0.00990 grams

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Answer 2

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