Question

The probability that a certain make of car will need repairs in the first four months is 0.5. A dealer sells five such cars. What is the probability that at least one of them will require repairs in the first four months? Round your final answer to four decimal places.

P(At least one car will require repairs)=

Answer 1

Probability that at least one of them will require repairs in the first four months

Binomial Problem with n = 5 ;

p(need repair) = 0.5;

p(not need) = 0.5

P(at least 1 need) = 1 - P(none need repair)
= 1 - 0.5^5
= 0.9687