A magnetic field is oriented at an angle of 46 ∘ to the normal of a...

Question

Question

A magnetic field is oriented at an angle of 46 ∘ to the normal of a rectangular area 4.8 cm by 6.0 cm.

If the magnetic flux through this surface has a magnitude of 5.0×10⁻⁵ T⋅m2 , what is the strength of the magnetic field (mT)?

Answer 1

Answer #1

The magnetic flux is

= BA*cos(theta)

B = / A*cos(theta)

B = 5 x 10^-5 T-m^2 / (4.8 x 10^-2 x 6 x 10^-2 x cos(46))

B = 0.025 T

B = 25 x 10^-3 T

B = 25 mT

Answer 2

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