In a random sample of 7 cell phones, the mean full retail price was $502.40 and...
In a random sample of
7 cell phones, the mean full retail price was $502.40 and the standard deviation was
$190.00 Further research suggests that the population mean is $427.17. Does the t-value for the original sample fall between −t 0.99 and t 0.99?
Assume that the population of full retail prices for cell phones is normally distributed.
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In a random sample of
7 cell phones, the mean full retail price was $502.40 and...
In a random sample of eleven cell phones, the mean full retail price was $460.50 and...
In a random sample of eleven cell phones, the mean full retail price was $460.50 and the standard deviation was $190.00. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 90% confidence interval for the population mean mu. Interpret the results. Identify the margin of error.
In a random sample of eight cell phones, the mean full retail price was $460.00 and...
In a random sample of eight cell phones, the mean full retail price was $460.00 and the standard deviation was $173.00. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 95% confidence interval for the population mean u. Interpret the results. Identify the margin of error. (Round to one decimal place as needed.) Construct a 95% confidence interval for the population mean. (Round to one decimal place as needed.) Interpret...
In a random sample of eight cell phones, the mean full retail price was $559.00 and...
In a random sample of eight cell phones, the mean full retail price was $559.00 and the standard deviation was $226 00. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 99% confidence interval for the population mean Interpret the results o Identify the margin of error (Round to one decimal place as needed) Construct a 99% confidence interval for the population mean IA (Round to one decimal place as...
1) In a random sample of eight cell phones, the mean full retail price was $526.50...
1) In a random sample of eight cell phones, the mean full retail price was $526.50 and the standard deviation was $184.00. Construct a 95% confidence interval for the true population price. Assume the sample was random and that the population of cell phone prices is normally distributed. Round your final answer to the nearest cent (2 numbers after the decimal)
In a random sample of eleven cell phones, the mean full retail price was $515.50 and...
In a random sample of eleven cell phones, the mean full retail price was $515.50 and the standard deviation was $212.00. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 90% confidence interval for the population mean mu. Interpret the results.
In a sample of 13 randomly selected high school seniors, the mean score on a standardized...
In a sample of 13 randomly selected high school seniors, the mean score on a standardized test was 1199 and the standard deviation was 166.0. Further research suggests that the population mean score on this test for high school seniors is 1017. Does the t-value for the original sample fall between -toos and boos? Assume that the population of test scores for high school seniors is normally distributed The t-value oft- fall between -0.99 and long because (Round to two...
Score: 0 of 1 pt HW Score: 27.5 %, 5.5 of 20 12 of 20 (7...
Score: 0 of 1 pt HW Score: 27.5 %, 5.5 of 20 12 of 20 (7 complete) Question Help 6.2.29-T In a sample of 12 randomly selected high school seniors, the mean score on a standardized test was 1175 and the standard deviation was 164.4. Further research suggests that the population mean score on this test for high school seniors is 1015 Does the t-value for the original sample fall between -to on and to on? Assume that the population...
Random sample of 11 completed auctions for phones, sample mean price of 795 and standard deviation...
Random sample of 11 completed auctions for phones, sample mean price of 795 and standard deviation of 22.15. we wish to make a 95% confidence interval for the population mean price, the t-critical value, t .025, is closest to:
i would use a t distribution because its a sample and its normally distrubted, im not...
i would use a t distribution because its a sample and its normally
distrubted, im not sure if thats correct
9. (0 points) Assume that all cell phone prices are normally distributed. In a random sample of 20 cell phones, you find that the mean price was $500 with a standard deviation of $180. If you would like to construct a 95%-confidence interval to estimate the population mean, what distribution would you use to find the margin of error? Explain...
A random sample of 15 statistics textbooks has a mean price of $105 with a standard...
A
random sample of 15 statistics textbooks has a mean price of $105
with a standard deviation of $30.25. Assume the distribution of
statistics textbook prices is not normally distributed.
10:13 Notes Done (c) A random sample of 15 statistics textbooks has a mean price of $105 with a standard deviation of $30.25. Assume the distribution of statistics textbook prices is not normally distributed. i) Critical value at 85% Confidence Level (indicate za/2 or ta/2): ii) Critical value at 95%...
In a random sample of eight cell phones, the mean full retail price was $460.00 and the standard deviation was $173.00. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 95% confidence interval for the population mean u. Interpret the results. Identify the margin of error. (Round to one decimal place as needed.) Construct a 95% confidence interval for the population mean. (Round to one decimal place as needed.) Interpret...
In a random sample of eight cell phones, the mean full retail price was $559.00 and the standard deviation was $226 00. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 99% confidence interval for the population mean Interpret the results o Identify the margin of error (Round to one decimal place as needed) Construct a 99% confidence interval for the population mean IA (Round to one decimal place as...
In a sample of 13 randomly selected high school seniors, the mean score on a standardized test was 1199 and the standard deviation was 166.0. Further research suggests that the population mean score on this test for high school seniors is 1017. Does the t-value for the original sample fall between -toos and boos? Assume that the population of test scores for high school seniors is normally distributed The t-value oft- fall between -0.99 and long because (Round to two...
Score: 0 of 1 pt HW Score: 27.5 %, 5.5 of 20 12 of 20 (7 complete) Question Help 6.2.29-T In a sample of 12 randomly selected high school seniors, the mean score on a standardized test was 1175 and the standard deviation was 164.4. Further research suggests that the population mean score on this test for high school seniors is 1015 Does the t-value for the original sample fall between -to on and to on? Assume that the population...
i would use a t distribution because its a sample and its normally
distrubted, im not sure if thats correct
9. (0 points) Assume that all cell phone prices are normally distributed. In a random sample of 20 cell phones, you find that the mean price was $500 with a standard deviation of $180. If you would like to construct a 95%-confidence interval to estimate the population mean, what distribution would you use to find the margin of error? Explain...
A
random sample of 15 statistics textbooks has a mean price of $105
with a standard deviation of $30.25. Assume the distribution of
statistics textbook prices is not normally distributed.
10:13 Notes Done (c) A random sample of 15 statistics textbooks has a mean price of $105 with a standard deviation of $30.25. Assume the distribution of statistics textbook prices is not normally distributed. i) Critical value at 85% Confidence Level (indicate za/2 or ta/2): ii) Critical value at 95%...
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